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A motorist drives north for 32.0 minutes at 80.5 km/h and then stops for 15.0 minutes. He then continues north, traveling 130 km in 1.80 h.(b) What is his average velocity?

Question

A motorist drives north for 32.0 minutes at 80.5 km/h and then stops for 15.0 minutes. He then continues north, traveling 130 km in 1.80 h.

(b) What is his average velocity?
check_circleAnswer
Step 1

We know that:

Average velocity=Total displacement
Total time
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Average velocity=Total displacement Total time

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Step 2

Let us find the total dispalc...

32
For first 32 mins (i.e.h), the motorist drives at 80.5 km/h
60
32
h) 42.933 km
60
Therefore, displacement during this period = 80.5 km/h x
=
15
For next 15 mins (i.e.), the motorist is at rest
60
Okm
Therefore, displacement during this period
For last 1.8 h, the motorist travels 130km
Therefore, displacement during this period 130km
Thus, total displacement = 172.9333 kn
32 15
+
And, total time
1.8 2.5833 h
60 60
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32 For first 32 mins (i.e.h), the motorist drives at 80.5 km/h 60 32 h) 42.933 km 60 Therefore, displacement during this period = 80.5 km/h x = 15 For next 15 mins (i.e.), the motorist is at rest 60 Okm Therefore, displacement during this period For last 1.8 h, the motorist travels 130km Therefore, displacement during this period 130km Thus, total displacement = 172.9333 kn 32 15 + And, total time 1.8 2.5833 h 60 60

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