A mysterious object is accelerated in a straight line across a table by a mysterious force. The force is not constant, but 100 varies depending on the position of the object. The graph and equations give the magnitude of the force F on the 80 object as a function of the position x of the object. 20 N x + 60 N 2 mm 0 mm < x < 2 mm 60 60 N F (x) = { 110N– 2 mm < x < 6 mm 40 4 mm 40 N -x – 40 N 4 mm 6 mm < x < 10 mm 20 2 4 8 10 Find the work W, done by the force on the object as it x (mm) travels from x = 2.00 mm to x = 9.00 mm. W. = J F(x) (N)

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter4: The Laws Of Motion
Section: Chapter Questions
Problem 8P: A 3.00-kg object is moving in a plane, with its x and y coordinates given by x = 5t2 1 and y = 3t3...
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A mysterious object is accelerated in a straight line across a
table by a mysterious force. The force is not constant, but
100
varies depending on the position of the object. The graph
and equations give the magnitude of the force F on the
80
object as a function of the position x of the object.
20 N
-x + 60 N
2 mm
O mm < x < 2 mm
60
60 N
F (x) :
110 N
X.
4 mm
2 mm < x < 6 mm
40
40 N
40 N
6 mm < x < 10 mm
4 mm
4
8
10
Find the work W, done by the force on the object as it
x (mm)
travels from x = 2.00 mm to x = 9.00 mm.
Wo =
J
F(x) (N)
20
Transcribed Image Text:A mysterious object is accelerated in a straight line across a table by a mysterious force. The force is not constant, but 100 varies depending on the position of the object. The graph and equations give the magnitude of the force F on the 80 object as a function of the position x of the object. 20 N -x + 60 N 2 mm O mm < x < 2 mm 60 60 N F (x) : 110 N X. 4 mm 2 mm < x < 6 mm 40 40 N 40 N 6 mm < x < 10 mm 4 mm 4 8 10 Find the work W, done by the force on the object as it x (mm) travels from x = 2.00 mm to x = 9.00 mm. Wo = J F(x) (N) 20
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