A new insecticide is advertised to kill more than 95% roaches upon contact. In a laboratory test, the insecticide was applied to 400 roaches and 384 died immediately after contact. Is this sufficient evidence to support the advertised claim? Use α=0.05. (c) p-value for the problem above i
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A new insecticide is advertised to kill more than 95% roaches upon contact. In a laboratory test, the insecticide was applied to 400 roaches and 384 died immediately after contact.
Is this sufficient evidence to support the advertised claim? Use α=0.05.
(c) p-value for the problem above i
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- If the df value for a two tailed test with alpha =0.05 were to increase from df=5 to df=22,what would happen to the critical values for t?Assuming all other factors are held constant ,if the df value for a two tailed t test with x=.05 were increased from df=6 to df=20,what would happen to the critical values for t? the critical values would further from t=0 the crtical values would move closer to t=0 the crtical values would not change this is impossible to determine1. A researcher reports an F-ratio with df(between) = 3 and df(within) = 28. How many treatment conditions were compared in the experiment? If samples have an equal number of participants, how many are in each treatment? 2. A researcher obtains an F = 4.10 with df = 2, 14. Is this value sufficient to reject the null with α = .05? Is it sufficient enough to reject the null with α = .01?
- For the situation described below, state the null and alternative hypotheses to be tested. (Enter != for ≠ as needed.) A seed wash is expected to change the proportion p of seeds that germinate when planted in poorly-draining soil. Suppose that the current germination rate is about 70%.Dr. Chapman conducted an experiment in which participants watched paint dry for 30 minutes twice, once being paid $1 and once being paid $30. When comparing the samples, he calculated t = 3.57. He assumed α = .01 with df = 5, so the tcv = ±4.032. Because the calculated value was: A. greater than the critical value, Dr. Chapman can reject the null hypothesis. B. greater than the critical value, Dr. Chapman failed to reject the null hypothesis. C. less than the critical value, Dr. Chapman failed to reject the null hypothesis. D. less than the critical value, Dr. Chapman can reject the null hypothesis.A sample of n = 16 scores produces a t statistic of t = 2.00. If the sample is used to measure effect size with r2, what value will be obtained for r2?
- See the attached image for the introduction. In terms of variables xi and parameters βi, write the null and alternative hypotheses for testing whether, after including Price/Square Feet(x2) in the model already, the further incorporation of the other 2 explanatory variables (x1, x3) adds any useful information for explaining pricey. Also, give the value of the F statistic and its degrees of freedom (df).Assume we wanted to show that the true proportion of virginica iris seeds that fail to germinate is less than 20%. Let's say we tested at an alpha of 0.05, and found a p-vale of 0.082. Which of the following would be an appropriate conclusion and interpretation? A) With an alpha of 0.05, and a p-value of 0.082, we fail to reject the null and state we have insufficient evidence to support that the true proportion of virginica iris seeds that fail to germinate is less than 20%. B) With an alpha of 0.05, and a p-value of 0.0082, we reject the null and state we have sufficient evidence to support that the true proportion of virginica iris seeds that fail to germinate is less than 20%. C) With an alpha of 0.05, and a p-value of 0.082, we reject the null and state we have sufficient evidence to support that the true proportion of virginica iris seeds that fail to germinate is less than 20%. D) With an alpha of 0.05, and a p-value of 0.082, we fail to reject the null and state…For the situation described below, state the null and alternative hypotheses to be tested. (Enter != for ≠ as needed.) A new variety of pearl millet is expected to provide an increased yield over the variety presently in use, which has a mean yield of about 55 bushels per acre.
- Researchers interested in lead exposure due to car exhaust sampled the blood of 52 police officers subjected to constant inhalation of automobile exhaust fumes while working traffic enforcement in a primarily urban environment. The blood samples of these officers had an average lead concentration of 124.32 µg/l and a SD of 37.74 µg/l; a previous study of individuals from a nearby suburb, with no history of exposure, found an average blood level concentration of 35 µg/l. Based on your preceding result, without performing a calculation, would a 99% confidence interval for the average blood concentration level of police officers contain 35 µg/l? Based on your preceding result, without performing a calculation, would a 99% confidence interval for this difference contain 0? Explain why or why not.Explain why the critical value of t, one-tailed, alpha = .05 is the same as the critical value of t, two-tailed, a .10 .To deal with the phenomenon of alpha inflation when doing multiple t-tests, what post-hoc tests such as the Bonferroni Correction do is _____. * Divide the critical value of t by the number of comparisons Multiply the alpha by the number of comparisons Divide the alpha level by the number of comparisons Multiply the critical value of t by the number of comparisons