A nitrate solution containing an unknown cation is added to each of the following three test tubes AAR 10 Mayo 1011 Ma 10M NOK A precipitate forms in one test tube only. The unknown cation is Ag O Ca²+ O Sr²+ Đ NHƯ
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- Just answer please label answer to questions so I know do all please 1. Stomach acid is approximately 0.10 M HCl. How many mL of stomach acid can be neutralized by one regular antacid tablet that contains 500 mg of solid CaCO3 (100.09 g/mol)? a. 1000b.50 c. 500 d. 100 e. 200 3. What is the formula of the precipitate that forms when aqueous NaCl and aqueous Hg2(NO3)2 are mixed?a. Hg2Cl2b. NaNO3 c.HgCl2 d. HgCl e. Hg2ClUse the following neutralization reaction to answer the questions: 2HCl(aq) + Ca(OH)2(aq) → CaCl2(aq) + 2H2O(l) Determine the number of moles of HCl needed to perfectly neutralize 0.037 moles of Ca(OH)2. Starting with 0.037 moles of Ca(OH)2, what would be the concentration of CaCl2(aq) if the total volume of the solution is 500.0mL?What volume in mL of a 0.113 M Ba(OH)2 solution is needed to neutralize 25.0 mL of a 0.103 M HCl solution? 2 HCl + Ba(OH)2 ---> BaCl2 + 2 H2O Group of answer choices 11.4 mL 12.8 mL 11.9 mL 12.5 mL
- Volume of HCL sample = 15ml Molarity standardized NaOh solution = .09929 Initial buret reading = 17.85 mL NaOH final buret reading = 36.16 mL NaOH What is the volume of NaOH used?when 15.00 mL of water is added to 5.25 mL of LiCl, what is the volume percent concentration (v/v%)A standard nitric acid solution is prepared using 0.425 g of sodium carbonate, Na2CO3. Find the molarity of the acid if 33.25 mL are required to reach a permanent endpoint.2 HNO3 (aq) + Na2CO3 (s) ➔ 2 NaNO3 (aq) + H2O(l) + CO2 (g)
- Water is the solvent of choice to separate a mixture of adipic acid and salicylic acid because it dissolves both substances easily. Group of answer choices True FalseVolume of HCL sample = 15ml Molarity standardized NaOh solution = .09929 Initial buret reading = 17.85 mL NaOH final buret reading = 36.16 mL NaOH volume of NaOH used = 17.31 Equation HCl = NaOH=NaCl + H2O How many moles of NaOH were used to reach the equivalence point?A student recrystallized 50 mg of impure salicylic acid and decided to wash the crystals with 1.0 mL of water at room temperature. What can happen? Group of answer choices the amount of crystals increase. the purity of the crystal increase. nothing will happen to the crystals. the amount of crystals decrease.
- It requires 24.15 mL of 0.03 M HCl to neutralize 38.2 mL of a NaOH solution. What is the concentration (M) of the NaOH solution? Please report your answer rounded to 4 decimal places. No units please.(a) Standardization of iodine solution ( finding its concentration ). 5.00 g vitamin C are dissolved in water to make 650 ml. solution. 15 ml of this solution is then titrated with 35 ml iodine solution to reach the endpoint ( blue color ). What is the molarity of the Iodine solution ? (b) Titration of vitamin C with the iodine solution from part (a). 8.0 ml of a vitamin C containing juice are titrated with the 55 ml of iodine solution to reach the endpoint. How many mg are there in 1 ml of this juice ?Answer the following questions for the reaction below: Ca(s) + 2HCl(aq) →CaCl2(aq) + H2(g) (a) How many mL of a 3.20 M HCl solution are required to react with 16.8 g of calcium? (b) How many liters of hydrogen gas under STP condition will form when 2.35 L of a 1.75 M HCl solution reacts?