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A one-way ANOVA was conducted at a = 0.05. The study involved three (3) different groups with 12 subjects in each. The means for each group were as follows: M, = 10.92, M2 = 13.83, and M, = 14.92. The sum of squares values is shown in the table below. Source Between-treatments S 102.72 df MS <.05 Within-treatments Total 229.50 332.22 a. Assuming a = 0.05, complete the rest of the table and write a verbal conclusion. b. Conduct a Tukey's HSD and indicate which means differ significantly.

A one-way ANOVA was conducted at a = 0.05. The study involved three (3) different groups with 12 subjects in each. The means for each group were as follows: M, = 10.92, M2 = 13.83, and M, = 14.92. The sum of squares values is shown in the table below. Source Between-treatments S 102.72 df MS <.05 Within-treatments Total 229.50 332.22 a. Assuming a = 0.05, complete the rest of the table and write a verbal conclusion. b. Conduct a Tukey's HSD and indicate which means differ significantly.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section4.5: Correlation And Causation
Problem 11PPS
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A one-way ANOVA was conducted at a = 0.05. The study involved three (3) different groups with 12 subjects in each. The means for each group were as follows: M, = 10.92, M, = 13.83, and M3 squares values is shown in the table below. Source Between-treatments = 14.92. The sum of %3D SS 102.72 df MS <.05 Within-treatments 229.50 332.22 Total a. Assuming a = 0.05, complete the rest of the table and write a verbal conclusion. b. Conduct a Tukey's HSD and indicate which means differ significantly.
Transcribed Image Text:A one-way ANOVA was conducted at a = 0.05. The study involved three (3) different groups with 12 subjects in each. The means for each group were as follows: M, = 10.92, M, = 13.83, and M3 squares values is shown in the table below. Source Between-treatments = 14.92. The sum of %3D SS 102.72 df MS <.05 Within-treatments 229.50 332.22 Total a. Assuming a = 0.05, complete the rest of the table and write a verbal conclusion. b. Conduct a Tukey's HSD and indicate which means differ significantly.
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