A parallel plate capacitor has a capacitance of 2.0 nF. The capacitor is initially charged such that the potential difference between the plates is 100 V with a dielectric between the plates of ruby mica (κ = 5.4). The capacitor is then disconnected from the power source.   a) How much work must be done to remove the ruby mica sheet? b) Determine the potential difference between the plates after the ruby mica sheet has been removed.

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter20: Electric Potential And Capacitance
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A parallel plate capacitor has a capacitance of 2.0 nF. The capacitor is initially charged
such that the potential difference between the plates is 100 V with a dielectric between
the plates of ruby mica (κ = 5.4). The capacitor is then disconnected from the power
source.  

a) How much work must be done to remove the ruby mica sheet?
b) Determine the potential difference between the plates after the ruby mica sheet has
been removed. 

Expert Solution
Step 1

Given,

     C = 2 nF = 2×10-9 F

    Vi = 100V   k  = 5.4

 

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