A parallel-plate capacitor of plate separation d charged to a potential difference AVg. A dielectric sl of thickness d and dielectric constant k is introduc between the plates while the battery remains co nected to the plates. (a) Show that the ratio of ener stored after the dielectric is introduced to the ener stored in the empty capacitor is U/U, = K. (b) Give physical explanation for this increase in stored ener (c) What happens to the charge on the capacitor? No This situation is not the same as in Example 26.5, which the battery was removed from the circuit befo

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter20: Electric Potential And Capacitance
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A parallel-plate capacitor of plate separation d is
charged to a potential difference AVg. A dielectric slab
of thickness d and dielectric constant k is introduced
between the plates while the battery remains con-
nected to the plates. (a) Show that the ratio of energy
stored after the dielectric is introduced to the energy
stored in the empty capacitor is U/U, = K. (b) Give a
physical explanation for this increase in stored energy.
(c) What happens to the charge on the capacitor? Note:
This situation is not the same as in Example 26.5, in
which the battery was removed from the circuit before
the dielectric was introduced.
Transcribed Image Text:A parallel-plate capacitor of plate separation d is charged to a potential difference AVg. A dielectric slab of thickness d and dielectric constant k is introduced between the plates while the battery remains con- nected to the plates. (a) Show that the ratio of energy stored after the dielectric is introduced to the energy stored in the empty capacitor is U/U, = K. (b) Give a physical explanation for this increase in stored energy. (c) What happens to the charge on the capacitor? Note: This situation is not the same as in Example 26.5, in which the battery was removed from the circuit before the dielectric was introduced.
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