A particle has a mass of 1.8×10–5 kg and a charge of 3×10–5 C. It is released from rest at point A and accelerates until it reaches point B, as shown in the figure. The particle moves on a horizontal straight line and does not rotate. The only forces acting on the particle are the gravitational force and an electrostatic force (neither is shown in the drawing). The electric potential at A is 25 V greater than that at B; in other words, VA – VB = 25 V. What is the translational speed of the particle at point B?
A particle has a mass of 1.8×10–5 kg and a charge of 3×10–5 C. It is released from rest at point A and accelerates until it reaches point B, as shown in the figure. The particle moves on a horizontal straight line and does not rotate. The only forces acting on the particle are the gravitational force and an electrostatic force (neither is shown in the drawing). The electric potential at A is 25 V greater than that at B; in other words, VA – VB = 25 V. What is the translational speed of the particle at point B?
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter2: Vectors
Section: Chapter Questions
Problem 4CQ: What do vectors and scalars have in common? How do they differ?
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A particle has a mass of 1.8×10–5 kg and a charge of 3×10–5 C. It is released from rest at point A and accelerates until it reaches point B, as shown in the figure. The particle moves on a horizontal straight line and does not rotate. The only forces acting on the particle are the gravitational force and an electrostatic force (neither is shown in the drawing). The electric potential at A is 25 V greater than that at B; in other words, VA – VB = 25 V. What is the translational speed of the particle at point B?
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