A particle having charge q = +1.80 µC and mass m = 0.0100 kg is connected to a string that is L = 1.80 m long and tied to the pivot point P in the figure below. The particle, string, and pivot point all lie on a frictionless, horizontal table. The particle is released from rest when the string makes an angle e = 60.0° with a uniform electric field of magnitude E = 340 V/m. Determine the speed of the particle when the string is parallel to the electric field. m/s y= 0 +q L. Ton view

Physics for Scientists and Engineers
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Chapter22: Electricity And Magnetism
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A particle having charge q = +1.80 µC and mass m = 0.0100 kg is connected to a string that is L = 1.80 m long and tied to the pivot point P in the figure below. The particle, string, and pivot point all lie on a
frictionless, horizontal table. The particle is released from rest when the string makes an angle e = 60.0° with a uniform electric field of magnitude E = 340 V/m. Determine the speed of the particle when the
string is parallel to the electric field.
m/s
m
v= 0
L
po
Тоp view
Transcribed Image Text:A particle having charge q = +1.80 µC and mass m = 0.0100 kg is connected to a string that is L = 1.80 m long and tied to the pivot point P in the figure below. The particle, string, and pivot point all lie on a frictionless, horizontal table. The particle is released from rest when the string makes an angle e = 60.0° with a uniform electric field of magnitude E = 340 V/m. Determine the speed of the particle when the string is parallel to the electric field. m/s m v= 0 L po Тоp view
Expert Solution
Step 1

Given that:

Charge of particle,q = 1.8uC

Mass of particle, m = 0.01 kg

Length of string, L = 1.8 m

angle = 60 degree

Magnitude, E  = 340 V/m

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