A particle is moving with acceleration a(t) = 36t + 8. its position at time t = 0 is s(0) = 17 and its velocity at time t = 0 is v(0) = 4. What is its position at time t = 6? %3D -

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A: Product Rule of differentiation : du.vdx = u.dvdx +dudx.v dxndx=n.xn-1 deaxdx=aeax Note : As per…

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A: The given problem is solved below in detail.

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Q: Question # 14 Rational Expression Reference Q. 15227 The rectangle shown has length 5æ2+ 10x cm and…

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Q: If f(x,y) %3D — 4y3 — 4ху — 12у — 3х? - 5х - 21 then fy equals ху O -6 -12y? – 4x - 12 | —4y — бх —…

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Q: Let f(T) 16 Using the definition of derivative at a point, f'(3) = lim f(x)- f(3) enter I - 3 the…

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