A particle moves according to a law of motion s = f(t), t 2 0, where t is measured in seconds and s in feet. (t) = te t/5 (a) Find the velocity at time t (in ft/s). v(t) = (t – 5)e 5 (b) What is the velocity after 2 s? (Round your answer to two decimal places.) v(2) = [0.40 ft/s (c) When is the particle at rest? t = [0 (d) When is the particle moving in the positive direction? (Enter your answer using interval notation.) [0,5) (e) Find the total distance traveled during the first 12 s. (Round your answer to two decimal places.) 1.09 X ft
A particle moves according to a law of motion s = f(t), t 2 0, where t is measured in seconds and s in feet. (t) = te t/5 (a) Find the velocity at time t (in ft/s). v(t) = (t – 5)e 5 (b) What is the velocity after 2 s? (Round your answer to two decimal places.) v(2) = [0.40 ft/s (c) When is the particle at rest? t = [0 (d) When is the particle moving in the positive direction? (Enter your answer using interval notation.) [0,5) (e) Find the total distance traveled during the first 12 s. (Round your answer to two decimal places.) 1.09 X ft
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 18T
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s= f(t) = te^(-t/5)
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