A particle moves along the x axis according to the equation x = 1.92 + 3.03t – 1.00t, where x is in meters and t is in seconds.(a) Find the position of the particle at t = 3.10 s.m(b) Find its velocity at t = 3.10 s.The instantaneous velocity at a particular time can be obtained by taking the time derivative of the position versus time function and then putting in the specific value of t. m/s(c) Find its acceleration at t = 3.10 s.The instantaneous acceleration at a particular time can be obtained by taking the second time derivative of the position versus time function and then putting in the specific value of t. m/sNeed Help?Read ItMaster It

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Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 48P: A commuter train travels between two downtown stations. Because the stations are only 1.00 km apart,...

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Using SI base units, a particle’s position as a function of time is given by x(t)=(7t3+4t2+6) m. (a) At what time will the particle’s acceleration be zero? (b) Find the speed of the particle at that time.
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