A particle moves along the x axis. It is initially at the position 0.310 m, moving with velocity 0.090 m/s and acceleration -0.320 m/s². Suppose it moves with constant acceleration for 4.40 s. (a) Find the position of the particle after this time. -2.39 m (b) Find its velocity at the end of this time interval. -1.32 ✓ m/s We take the same particle and give it the same initial conditions as before. Instead of having a constant acceleration, it oscillates in simple harmonic motion for 4.40 s around the equilibrium position x = 0. Hint: the following problems are very sensitive to rounding, and you should keep all digits in your calculator. (c) Find the angular frequency of the oscillation. Hint: in SHM, a is proportional to x. 0.143 X Your response differs from the correct answer by more than 10%. Double check your calculations. /s (d) Find the amplitude of the oscillation. Hint: use conservation of energy. 0.316 (e) Find its phase constant po if cosine is used for the equation of motion. Hint: when taking the inverse of a trig function, there are always two angles but your calculator will tell you only one and you must decide which of the two angles you need. -0.195 X Your response differs from the correct answer by more than 10%. Double check your calculations. rad (f) Find its position after it oscillates for 4.40 s. -0.310 Your response differs from the correct answer by more than 10%. Double check your calculations. m (g) Find its velocity at the end of this 4.40 s time interval. 0.090 X Your response differs from the correct answer by more than 10%. Double check your calculations. m/s
A particle moves along the x axis. It is initially at the position 0.310 m, moving with velocity 0.090 m/s and acceleration -0.320 m/s². Suppose it moves with constant acceleration for 4.40 s. (a) Find the position of the particle after this time. -2.39 m (b) Find its velocity at the end of this time interval. -1.32 ✓ m/s We take the same particle and give it the same initial conditions as before. Instead of having a constant acceleration, it oscillates in simple harmonic motion for 4.40 s around the equilibrium position x = 0. Hint: the following problems are very sensitive to rounding, and you should keep all digits in your calculator. (c) Find the angular frequency of the oscillation. Hint: in SHM, a is proportional to x. 0.143 X Your response differs from the correct answer by more than 10%. Double check your calculations. /s (d) Find the amplitude of the oscillation. Hint: use conservation of energy. 0.316 (e) Find its phase constant po if cosine is used for the equation of motion. Hint: when taking the inverse of a trig function, there are always two angles but your calculator will tell you only one and you must decide which of the two angles you need. -0.195 X Your response differs from the correct answer by more than 10%. Double check your calculations. rad (f) Find its position after it oscillates for 4.40 s. -0.310 Your response differs from the correct answer by more than 10%. Double check your calculations. m (g) Find its velocity at the end of this 4.40 s time interval. 0.090 X Your response differs from the correct answer by more than 10%. Double check your calculations. m/s
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
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Transcribed Image Text:A particle moves along the x axis. It is initially at the position 0.310 m, moving with velocity 0.090 m/s and acceleration
-0.320 m/s². Suppose it moves with constant acceleration for 4.40 s.
(a) Find the position of the particle after this time.
-2.39
m
(b) Find its velocity at the end of this time interval.
-1.32
✓ m/s
We take the same particle and give it the same initial conditions as before. Instead of having a constant acceleration, it
oscillates in simple harmonic motion for 4.40 s around the equilibrium position x = 0. Hint: the following problems are very
sensitive to rounding, and you should keep all digits in your calculator.
(c) Find the angular frequency of the oscillation. Hint: in SHM, a is proportional to x.
0.143
X
Your response differs from the correct answer by more than 10%. Double check your calculations. /s
(d) Find the amplitude of the oscillation. Hint: use conservation of energy.
0.316
(e) Find its phase constant if cosine is used for the equation of motion. Hint: when taking the inverse of a trig
function, there are always two angles but your calculator will tell you only one and you must decide which of the
two angles you need.
-0.195
X
Your response differs from the correct answer by more than 10%. Double check your calculations. rad
(f) Find its position after it oscillates for 4.40 s.
-0.310
Your response differs from the correct answer by more than 10%. Double check your calculations. m
(g) Find its velocity at the end of this 4.40 s time interval.
0.090
X
Your response differs from the correct answer by more than 10%. Double check your calculations. m/s
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