A particle starts from rest and moves in a straight line on a smooth horizontal surface. Its acceleration at time t seconds is k(4v + 1) m s-², where k is a positive constant and v ms- is e2 the speed of the particle. Given that v = when t = 1, show that 4 v =(e2t – 1). ( Take g as 10 m s?.)

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Chapter1: Units, Trigonometry. And Vectors
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A particle starts from rest and moves in a straight line on a smooth horizontal surface.
Its acceleration at time t seconds is k(4v + 1) m s-², where k is a positive constant and v ms- is
e2
the speed of the particle. Given that v =
when t = 1, show that
4
v =(e2t – 1).
( Take g as 10 m s?.)
Transcribed Image Text:A particle starts from rest and moves in a straight line on a smooth horizontal surface. Its acceleration at time t seconds is k(4v + 1) m s-², where k is a positive constant and v ms- is e2 the speed of the particle. Given that v = when t = 1, show that 4 v =(e2t – 1). ( Take g as 10 m s?.)
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