A particle starts moving from (- 4, 2, 5) so that its initial velocity is 5 î -3 ĵ – 2k and its acceleration vector is a(t) = (2 t+3) î + (4 t – 1) ĵ +6k then after one minute, the particle will be at the point: 1) (용,-풍, 1) ,1) 2) ( 5, 3, 6 ) 6 6 3) (, -4) 4) (풍,-8,6) 17 17 5 6. 6

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.4: The Dot Product
Problem 32E
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elearning.ahu.edu.jo
A particle starts moving from
(- 4, 2, 5) so that its initial
velocity is 5 î - 3 ĵ-2k and
its acceleration vector is
a(t) = (2 t+ 3) î + (4t -1) ĵ + 6k
then after one minute, the particle
will be at the point:
41
17
2) (5, 3, 6)
3) (공, -8,4) 4)(물, -동, 6)
Select one:
1 X
2
3
4
The correctancwer is: 4
و بحث. . .
טך
...
Transcribed Image Text:elearning.ahu.edu.jo A particle starts moving from (- 4, 2, 5) so that its initial velocity is 5 î - 3 ĵ-2k and its acceleration vector is a(t) = (2 t+ 3) î + (4t -1) ĵ + 6k then after one minute, the particle will be at the point: 41 17 2) (5, 3, 6) 3) (공, -8,4) 4)(물, -동, 6) Select one: 1 X 2 3 4 The correctancwer is: 4 و بحث. . . טך ...
elearning.ahu.edu.jo
A particle starts moving from
(2, 4, -3) so that its velocity is
v(t) = (3t+2t+1) î +t³ ĵ +6t²k
then after 2 minutes the particle
will be at the point:
1) (16, 8, 19)
3) (14, 4, 16)
2) (17, 8, 24)
4) (16, 8, 13 )
Select one:
1
2
3 X
4
The correct answer is: 4
و بحث. . .
טך
...
Transcribed Image Text:elearning.ahu.edu.jo A particle starts moving from (2, 4, -3) so that its velocity is v(t) = (3t+2t+1) î +t³ ĵ +6t²k then after 2 minutes the particle will be at the point: 1) (16, 8, 19) 3) (14, 4, 16) 2) (17, 8, 24) 4) (16, 8, 13 ) Select one: 1 2 3 X 4 The correct answer is: 4 و بحث. . . טך ...
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