The scalar equation of the plane with normal vector [4, -1, 9] and passing through the point (2, -1, -1) is: 4x - y+ 9z 0 4x-y-9z 0 O4x-y+ 9z + 7 = 0 O4x+y+9z = 0

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter8: Applications Of Trigonometry
Section8.4: The Dot Product
Problem 12E
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The scalar equation of the plane with normal vector [4, -1, 9] and passing through
the point (2, -1, -1) is:
4x-y+ 9z 0
4x-y-9z 0
4x-y+ 9z + 7 = 0
4 x+y+ 9z = 0
Transcribed Image Text:The scalar equation of the plane with normal vector [4, -1, 9] and passing through the point (2, -1, -1) is: 4x-y+ 9z 0 4x-y-9z 0 4x-y+ 9z + 7 = 0 4 x+y+ 9z = 0
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