A person driving on I-82 glanced at his phone to read a very important text message.  When he looked back up at the road, he saw that the traffic ahead had come to a standstill and he immediately slammed on his brakes.  His car created 96.5 m long skid marks before rear-ending another car.  Unfortunately, a passenger in the rear-ended car was seriously injured, thus requiring an investigation by the State Patrol.  The State Patrol has no proof of distracted driving, however they want to determine if a citation for speeding should be issued.   A State Patrol investigator used a 3.9 kg drag sled to determine the coefficient of kinetic friction between the road and the tires of the car.  The drag sled’s spring scale read 28 N when it was pulled along the ground at a constant speed.   Use Newton’s Second Law and kinematics to estimate the minimum value of the car’s speed when the driver locked the brakes. (answer: about 83 mi/hr)   Note: You do not need the mass of the car to answer this question.   FNET = ma  fk = kN  W = mg g = 9.81 m/s2 v2 = v02 + 2ax  1 mi/hr = 0.45 m/s

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Chapter1: Units, Trigonometry. And Vectors
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A person driving on I-82 glanced at his phone to read a very important text message.  When he looked back up at the road, he saw that the traffic ahead had come to a standstill and he immediately slammed on his brakes.  His car created 96.5 m long skid marks before rear-ending another car.  Unfortunately, a passenger in the rear-ended car was seriously injured, thus requiring an investigation by the State Patrol.  The State Patrol has no proof of distracted driving, however they want to determine if a citation for speeding should be issued.

 

A State Patrol investigator used a 3.9 kg drag sled to determine the coefficient of kinetic friction between the road and the tires of the car.  The drag sled’s spring scale read 28 N when it was pulled along the ground at a constant speed.

 

Use Newton’s Second Law and kinematics to estimate the minimum value of the car’s speed when the driver locked the brakes. (answer: about 83 mi/hr)

 

Note: You do not need the mass of the car to answer this question.

 

FNET = ma  fk = kN  W = mg g = 9.81 m/s2

v2 = v02 + 2ax  1 mi/hr = 0.45 m/s

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