A person makes a quantity of iced tea by mixing 200 g of hot tea (essentially water) with an equal mass of ice at its melting point. Assume the mixture has negligible energy exchanges with its environment. (a) If the tea's initial temperature is T; = 81°C, when thermal equilibrium is reached what are the mixture's temperature Trand (b) the remaining mass m;of ice? If T; = 53°C, when thermal equilibrium is reached what are (c) Trand (d) m2 The specific heat of water is 4186 J/kg-K. The latent heat of fusion is 333 kJ/kg. (a) Number i 16 Units (b) Number i o kg Units (c) Number i o Units (d) Number i Units kg > >

A person makes a quantity of iced tea by mixing 200 g of hot tea (essentially water) with an equal mass of ice at its melting point. Assume the mixture has negligible energy exchanges with its environment. (a) If the tea's initial temperature is T; = 81°C, when thermal equilibrium is reached what are the mixture's temperature Trand (b) the remaining mass m;of ice? If T; = 53°C, when thermal equilibrium is reached what are (c) Trand (d) m2 The specific heat of water is 4186 J/kg-K. The latent heat of fusion is 333 kJ/kg. (a) Number i 16 Units (b) Number i o kg Units (c) Number i o Units (d) Number i Units kg > >

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter1: Temperature And Heat

Section: Chapter Questions

Problem 80P: How many grams of coffee must evaporate from 350 g of coffee in a 100-g glass cup to cool the coffee...

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In the laboratory, calorimetry can be used to determine the latent heat of fusion of water, LfLf. If an ice cube of mass 30.0g30.0g at 0∘C0∘C is added to a calorimeter cup of mass mc=60.0gmc=60.0g that contains water of mass 170g170g at an initial temperature TiwTiw of 20∘C20∘C, after the ice melts, the final temperature of the water TfwTfw is found to be 5.57∘C5.57∘C. Based on this data, what is the latent heat of fusion of water? The specific heat capacities of water and the calorimeter are 4186J/(kg.K)4186J/(kg.K) and 900J/(kg.K)900J/(kg.K), respectively
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