Instructions:make an explanation of the results obtained. Note:(the exercise is in the images), (in the other image, is the answer, but I want to know the explanation of the obtained results)I am a high school student and I would like to know that A pharmaceutical company manufacturing the Paracetamol tablets with the Average weight of 500 mg andpopulation variance of 36 mg. A quality officer in a company wants to investigate whether the weight ofParacetamol tablets is differed from 500 mg. To investigate He taken 50 tablets at the time of manuracturingand find that the average weight of 5o tablets is 504.5 mg.Make the hypothesis test that the average weight of tablets is differ from or not at 95% confidence level. Step 1- Hypotheses -:Null hypothesis H,: u = 500 (or) The population average weight of tablets is equal to 500 mgAlternative hypothesis H,: u# 500 (or) The population average weight of tablets is not equal to 500 mgStep 2 - Calculation of z test statistic:Given values are,x bar = sample mean = 504.5 mgH = population mean = 500 mgo = Population standard deviation =6 [ because population variance o = 36]n= sample size = 50Substitute the above values in z test statistic formula as given= zvn504.5-500V504.56/7.0714.50.85= 5.30Thus, the z test statistic is 5.30Step 3:z-table value:Given Significance level is a = 0.05.Now, Za/2 is the z critical value at 95% confidence level is ±1.96 (refer from the standard normal z table valuesi.e., Za/2 = Z0.05/2 =±1.96step 4 - Rejection rule:we rejecting null hypothesis H, if z test statistic value outside the range of z critical values. otherwise acceptnull hypothesis H, at 95% confidence level.Step 5- Conclusion:Since, the z test statistic (5.30) is outside the z critical values of (-1.96 to +1.96). Thus, we have sufficientevidence to reject the null hypothesis H, at 95% confidence level.Hence, null hypothesis H, is rejected.So, the average weight of tablets is not equal to 500 mg

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Instructions:make an explanation of the results obtained. Note:(the exercise is in the images), (in the other image, is the answer, but I want to know the explanation of the obtained results)I am a high school student and I would like to know that A pharmaceutical company manufacturing the Paracetamol tablets with the Average weight of 500 mg andpopulation variance of 36 mg. A quality officer in a company wants to investigate whether the weight ofParacetamol tablets is differed from 500 mg. To investigate He taken 50 tablets at the time of manuracturingand find that the average weight of 5o tablets is 504.5 mg.Make the hypothesis test that the average weight of tablets is differ from or not at 95% confidence level. Step 1- Hypotheses -:Null hypothesis H,: u = 500 (or) The population average weight of tablets is equal to 500 mgAlternative hypothesis H,: u# 500 (or) The population average weight of tablets is not equal to 500 mgStep 2 - Calculation of z test statistic:Given values are,x bar = sample mean = 504.5 mgH = population mean = 500 mgo = Population standard deviation =6 [ because population variance o = 36]n= sample size = 50Substitute the above values in z test statistic formula as given= zvn504.5-500V504.56/7.0714.50.85= 5.30Thus, the z test statistic is 5.30Step 3:z-table value:Given Significance level is a = 0.05.Now, Za/2 is the z critical value at 95% confidence level is ±1.96 (refer from the standard normal z table valuesi.e., Za/2 = Z0.05/2 =±1.96step 4 - Rejection rule:we rejecting null hypothesis H, if z test statistic value outside the range of z critical values. otherwise acceptnull hypothesis H, at 95% confidence level.Step 5- Conclusion:Since, the z test statistic (5.30) is outside the z critical values of (-1.96 to +1.96). Thus, we have sufficientevidence to reject the null hypothesis H, at 95% confidence level.Hence, null hypothesis H, is rejected.So, the average weight of tablets is not equal to 500 mg

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