A piece of copper wire has a resistance per unit length of 4.63 x 10/m. The wire is wound into a thin, flat coil of many turns that has a radius of 0.208 m. The ends of the wire are connected to a 12.0-V battery. Find the magnetic field strength at the center of the coil.

A piece of copper wire has a resistance per unit length of 4.63 x 10/m. The wire is wound into a thin, flat coil of many turns that has a radius of 0.208 m. The ends of the wire are connected to a 12.0-V battery. Find the magnetic field strength at the center of the coil.

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter12: Sources Of Magnetic Fields

Section: Chapter Questions

Problem 12.2CYU: Check Your Understanding The wire loop forms a full circle of radius R and current I. What is the...

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Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

Question

A piece of copper wire has a resistance
per unit length of 4.63 × 10/m. The wire
is wound into a thin, flat coil of many turns
that has a radius of 0.208 m. The ends of
the wire are connected to a 12.0-V
battery. Find the magnetic field strength
at the center of the coil.
Number
i
Units
>

Expert Solution

Step 1

Given

Resistance per unit length = 4.63 × 10^-3 ohm/m

Applied potential difference V = 12 Volt

Radius of coil = 0.208 m

Step by step

Solved in 2 steps with 1 images

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