A piece of wire 40 cm long is to be cut into two pieces. One piece will be bent to form a circle, the other will be bent to form a square. Find the lengths of the two pieces that cause the sum of the area of the circle and the are of the square be a minimum. Circumference of the Circle= 17.596 cm, Perimeter of the Square 22.404 cm

Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter63: Volumes Of Pyramids And Cones
Section: Chapter Questions
Problem 34A
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A piece of wire 40 cm long is to be cut into two pieces. One piece will be 1
bent to forma circle, the other will be bent to form a square. Find the
lengths of the two pieces that cause the sum of the area of the circle and
the are of the square be a minimum.
O Circumference of the Circle= 17.596 cm, Perimeter of the Square= 22.404 cm
O Circumference of the Circle= 20.333 cm, Perimeter of the Square= 17.656 cm
O Circumference of the Circle= 10.266 cm, Perimeter of the Square= 32.112 em
O Circumference of the Circle= 16.742 cm, Perimeter of the Square= 23.442 cm
Transcribed Image Text:A piece of wire 40 cm long is to be cut into two pieces. One piece will be 1 bent to forma circle, the other will be bent to form a square. Find the lengths of the two pieces that cause the sum of the area of the circle and the are of the square be a minimum. O Circumference of the Circle= 17.596 cm, Perimeter of the Square= 22.404 cm O Circumference of the Circle= 20.333 cm, Perimeter of the Square= 17.656 cm O Circumference of the Circle= 10.266 cm, Perimeter of the Square= 32.112 em O Circumference of the Circle= 16.742 cm, Perimeter of the Square= 23.442 cm
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