Asked Oct 17, 2019

A piston is seated at the top of a cylindrical chamber with radius 5 cm when it starts moving into the chamber at a constant speed of 3 cm/s. What is the rate of change of the volume of the cylinder when the piston is 2 cm from the base of the chamber?


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The radius of the piston is 5 cm The piston moving through the downward at the rate of 3 cm per second. dh =-3 dt cm That is, the value of _. Note that, the negative sign occurs for downward speed of the piston. It is known that, the formula for the volume of the cylinder V 7r2h Differentiate V= 7r2h the with respect to t dV d dt dt = ahh dt


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