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Asked Dec 6, 2019
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A pitcher throws a 0.25 kg ball of clay at a stationary 3.0 kg block of wood. The Clay sticks to the wood on impact. The joint speed of the combined mass (clay plus wood) is 2 m/s. Calculate the original speed of the clay. 

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Step 1

Let v1 be the initial speed of the ball, and v be the final speed of the combined mass, m be the mass of ball, and M be the mass of...

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my; = (m+ M )v (m + M) (0.25 kg +3 kg) = (2 m/s) 0.25 kg = 26 m/s

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