A point charge q1 =8.0 nC is at the origin and another point charge q2 = 12.0 nC is on the x-axis at x=4.0 m. Find the electric field at (x=0,y=3.0 m). Express all numerical values in three significant figures. Calculate the electric field component due to each point charge. Fill out the table below. Express all numerical values in three significant figures. Do not forget to include the sign if the value is negative. E, (N/c) E, (N/c) electric field due to charge 1 E1 electric field due to charge 2 E2 net electric field From the components of the net electric field, we can calculate its magnitude using Pythagorean theorem. Thus the value of the net electric field magnitude is N/C

College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter19: Electric Potential And Electric Field
Section: Chapter Questions
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Question 6 please… thank youuu!
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Since a single electron has a charge of -1.60 × 10-19 C, the number of electrons passing through the filament in t=5.00 S is:
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QUESTION 6
A point charge q =8.0 nC is at the origin and another point charge g, =12.0 nC is on the x-axis at X=4.0 m. Find the electric field at
(x=0, y=3.0 m). Express all numerical values in three significant figures.
Calculate the electric field component due to each point charge. Fill out the table below. Express all numerical values in three significant figures. Do not forget to
include the sign if the value is negative.
E, (N/c)
Ey (N/c)
electric field due to charge 1 E
electric field due to charge 2 E2
net electric field
From the components of the net electric field, we can calculate its magnitude using Pythagorean theorem. Thus the value of the net electric field magnitude is
N/C
Click Save and Submit to save and submit. Click Save All Answers to save all answers.
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Transcribed Image Text:bo O ACTI C x 4 4th c A drive O Clan P Not M Sign Que: A drive m mCc UP UP C O myGO E da Acce A Al A ust.blackboard.com/ultra/courses/_168281_1/c/outline pps M Gmail YouTube Maps y Image * Question Completion Status: =4.175 COUIOMDS Since a single electron has a charge of -1.60 × 10-19 C, the number of electrons passing through the filament in t=5.00 S is: N= .61 × 1019 electrons QUESTION 6 A point charge q =8.0 nC is at the origin and another point charge g, =12.0 nC is on the x-axis at X=4.0 m. Find the electric field at (x=0, y=3.0 m). Express all numerical values in three significant figures. Calculate the electric field component due to each point charge. Fill out the table below. Express all numerical values in three significant figures. Do not forget to include the sign if the value is negative. E, (N/c) Ey (N/c) electric field due to charge 1 E electric field due to charge 2 E2 net electric field From the components of the net electric field, we can calculate its magnitude using Pythagorean theorem. Thus the value of the net electric field magnitude is N/C Click Save and Submit to save and submit. Click Save All Answers to save all answers. riv er MacBook Air esc 000 D00 EA FI F2 F3 F5 F6 F7 F8 F9 @ € % & *3 # 3 4 6 7 8 9 Q W E R T
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