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A point charge q1 = -4.00 nC is at the point x = 0.60 m, y = 0.80 m , and a second point charge q2 = +6.00 nC is at the point x = 0.60 m , y = 0.Calculate the magnitude of the net electric field at the origin due to these two point charges.Calculate the direction of the net electric field at the origin due to these two point charges.

Question

A point charge q1 = -4.00 nC is at the point x = 0.60 m, y = 0.80 m , and a second point charge q2 = +6.00 nC is at the point x = 0.60 m , y = 0.

Calculate the magnitude of the net electric field at the origin due to these two point charges.

Calculate the direction of the net electric field at the origin due to these two point charges.
 
check_circleAnswer
Step 1

Magnitude of electric field due to q1 at origin is,

ką
(8.99x10 Nm'C2)(4.00x10°C)
(0.60m)+(0.80m)
35.96 NC
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ką (8.99x10 Nm'C2)(4.00x10°C) (0.60m)+(0.80m) 35.96 NC

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Step 2

Magnitude of electric field due to q2 at origin is,

kqr
E2
(8.99x10° Nm C2)(6.00 x10C)
(0.60m)(0.00m)
=149.83 N C
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kqr E2 (8.99x10° Nm C2)(6.00 x10C) (0.60m)(0.00m) =149.83 N C

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Step 3

Location of q1 with respect to...

0= tan *1 0.80m
0.60m
-53.130
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0= tan *1 0.80m 0.60m -53.130

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Science

Physics

Electric Charges and Fields

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