A point particle of charge q = 10 µc is at the center of an uncharged conducting spherical shell of inner radius a = 4 cm and outer radius = 10 cm . Find: a. The surface charge density at the outer surface of the shell. b. The electric field at r = 20 cm from center. c. The electric flux through a spherical surface of radius 6 cm with its center at the center of the shell.

A point particle of charge q = 10 µc is at the center of an uncharged conducting spherical shell of inner radius a = 4 cm and outer radius = 10 cm . Find: a. The surface charge density at the outer surface of the shell. b. The electric field at r = 20 cm from center. c. The electric flux through a spherical surface of radius 6 cm with its center at the center of the shell.

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter6: Gauss's Law

Section: Chapter Questions

Problem 70P: A point charge q=5.01012 C is placed at the center of a spherical conducting shell of inner radius...

See similar textbooks

Similar questions

A particle with charge Q is located a small distance immediately above the center of the flat face of a hemisphere of radius R as shown in Figure P19.38. What is the electric flux (a) through the curved surface and (b) through the flat face as 0?
What is the magnitude of the electric field just above the middle of a large, flat, horizontal sheet carrying a charge density of 98.0 nC/m2?
(a) If the electric flux through a closed surface is zero, is the electric field necessarily zero at all points on the surface? (b) What is the net charge inside the surface?
Figure 2 shows a nonconducting rod with a uniformly distributed charge Q. The rod forms a half-circle with radius R and produces an electric field of magnitude Earc at its center of curvature P. If the arc is collapsed to a point at distance R from P, by what factor is the magnitude of the electric field at P multiplied?
A solid nonconducting sphere of radius R = 6.7 cm has a nonuniform charge distribution of volume charge density ρ = (16.7 pC/m3)r/R, where r is radial distance from the sphere's center. (a) What is the sphere's total charge? What is the magnitude E of the electric field at (b) r = 0, (c) r = R/2.0, and (d) r = R? *I don't need answer a. * hint: Did you construct a Gaussian sphere through any given radial point, concentric with the actual sphere? What is the charge enclosed by the Gaussian sphere? (Do you see that with a variable density, integration is required?) Did you then apply Gauss' law to get the field?
A charge of + 8 uC is evenly distributed over the volume of an insulating sphere of 6 cm radius. Gauss using the law of charge distribution center a) r = 4 cm and b) electric field at r = 8 cm distances find? c) Find the electric flux through a Gaussian surface given at r = 8 cm? NOTE: Englısh not my tongue language so sometimes i cant reading handwriting can u use computer ? thanks
A solid insulating sphere of radius 0.07 m carries a total charge of 25 uC. Concentric with this sphere is a conducting spherical shell of inner radius 0.12 m and outer radius of 0.18 m, and carrying total charge of -54 uC. Find (a) the charge distribution for the insulating sphere and the conducting spherical shell, and the magnitude of the electric field at the follwing distances from the center of the two spheres and shell: (b) 0.05 m, (c) 0.10 m, (d) 0.15 m, and (e) 0.25 m.
An infinite line charge has constant charge-per-unit-length λ. Surrounding the line charge is a cylindrical shell of radius R, and carrying a constant charge-per-unit area σ. Given λ, what must σ be in order to get 0 electric field for all points outside the cylindrical shell? For that σ, what is the electrical field in between the line of charge and shell?
what can you conclude about the relationship among the electric flux, electric field lines, and the charge enclosed by the surface?
A negative charge (-6 uC) is spread uniformly over the shell with a radius of 8 cm. Insude this hollow shell is a solid sphere with a positive charge of 8uC and a radius of 6 cmAt a point outside the shell and is 12 cm from the center of the sphere,a. Determine the total electric fluxb. Find the magnitude of the electric field, expressed in MN/C
The electric flux through an arbitrary closed surafce is ϕ=52Nm2/C. What is the charge enclosed by that closed surface? Charge enclosed by the surface is
(a) Calculate the electric flux through the open hemispherical surface due to the electric field E =E0k (see below). (b) If the hemisphere is rotated by 90( around the what is the flux through it?