A projectile is fired with a velocity u from an inclined angle of beta. The projectile makes an angle of alpha with the horizontal. (i) If (usin(a) — ½gt) cos(ß) = usin(ß)cos (a) show that t = 2usin(a-B)sec (B) g where g is acceleration due to gravity and t is time of flight. u² (ii) where R is the range of If gR = u²sec² (ß)[1 – sin (ß)], show that R = the projectile. g[1+sin(B)]
A projectile is fired with a velocity u from an inclined angle of beta. The projectile makes an angle of alpha with the horizontal. (i) If (usin(a) — ½gt) cos(ß) = usin(ß)cos (a) show that t = 2usin(a-B)sec (B) g where g is acceleration due to gravity and t is time of flight. u² (ii) where R is the range of If gR = u²sec² (ß)[1 – sin (ß)], show that R = the projectile. g[1+sin(B)]
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![A projectile is fired with a velocity u from an inclined angle of beta. The projectile makes an
angle of alpha with the horizontal.
2usin(a-B)sec (B)
(i) If (usin(a) — 2½ gt) cos(B) = usin(ß)cos (a) show that t =
g
where g is acceleration due to gravity and this time of flight.
u2
(ii)
=
where R is the range of
If gR = u²sec² (B)[1 - sin (B)], show that R
the projectile.
g[1+sin(3)]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4e0bd390-9dd6-4091-bf37-0366077fae4b%2F7ca603a8-6e7c-422e-8e70-cb29e4f132e2%2Fu5hnvh_processed.png&w=3840&q=75)
Transcribed Image Text:A projectile is fired with a velocity u from an inclined angle of beta. The projectile makes an
angle of alpha with the horizontal.
2usin(a-B)sec (B)
(i) If (usin(a) — 2½ gt) cos(B) = usin(ß)cos (a) show that t =
g
where g is acceleration due to gravity and this time of flight.
u2
(ii)
=
where R is the range of
If gR = u²sec² (B)[1 - sin (B)], show that R
the projectile.
g[1+sin(3)]
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