A projectile is shot from the edge of a cliff 115 m above ground level with an initial speed of vo = 59 m/s at an angle of 35.0° with the horizontal, as shown in the figure (Figure 1). Figure < 1 of 1 135.0 h =i15m

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Chapter1: Units, Trigonometry. And Vectors
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Part D
A projectile is shot from the edge of a cliff 115 m above
ground level with an initial speed of vo = 59 m/s at an
angle of 35.0° with the horizontal, as shown in the figure
(Figure 1).
At the instant just before the projectile hits point P, find the magnitude of the velocity.
Express your answer to three significant figures and include the appropriate units.
HÀ
?
V =
Value
Units
Submit
Request Answer
Part E
At the instant just before the projectile hits point P, find the angle made by the velocity vector with the horizontal.
Express your answer to three significant figures and include the appropriate units.
HẢ
?
Figure
1 of 1
=
Value
Units
below the horizon
Submit
Request Answer
[35.0°
Part F
h = 115 m
Find the maximum height above the cliff top reached by the projectile.
Express your answer to three significant figures and include the appropriate units.
HÀ
?
Transcribed Image Text:Part D A projectile is shot from the edge of a cliff 115 m above ground level with an initial speed of vo = 59 m/s at an angle of 35.0° with the horizontal, as shown in the figure (Figure 1). At the instant just before the projectile hits point P, find the magnitude of the velocity. Express your answer to three significant figures and include the appropriate units. HÀ ? V = Value Units Submit Request Answer Part E At the instant just before the projectile hits point P, find the angle made by the velocity vector with the horizontal. Express your answer to three significant figures and include the appropriate units. HẢ ? Figure 1 of 1 = Value Units below the horizon Submit Request Answer [35.0° Part F h = 115 m Find the maximum height above the cliff top reached by the projectile. Express your answer to three significant figures and include the appropriate units. HÀ ?
Determine the time taken by the projectile to hit point P at ground level.
Express your answer to three significant figures and include the appropriate units.
A projectile is shot from the edge of a cliff 115 m above
ground level with an initial speed of vo = 59 m/s at an
angle of 35.0° with the horizontal, as shown in the figure
(Figure 1).
HÀ
?
t =
Value
Units
Submit
Request Answer
Part B
Determine the distance X of point P from the base of the vertical cliff.
Express your answer to three significant figures and include the appropriate units.
HA
?
X =
Value
Units
Figure
1 of 1
Submit
Request Answer
Part C
35.0
At the instant just before the projectile hits point P, find the horizontal and the vertical components of its velocity.
Express your answers using three significant figures separated by a comma.
h =15 m
ΑΣφ.
?
Vx , Vy =
m/s
Transcribed Image Text:Determine the time taken by the projectile to hit point P at ground level. Express your answer to three significant figures and include the appropriate units. A projectile is shot from the edge of a cliff 115 m above ground level with an initial speed of vo = 59 m/s at an angle of 35.0° with the horizontal, as shown in the figure (Figure 1). HÀ ? t = Value Units Submit Request Answer Part B Determine the distance X of point P from the base of the vertical cliff. Express your answer to three significant figures and include the appropriate units. HA ? X = Value Units Figure 1 of 1 Submit Request Answer Part C 35.0 At the instant just before the projectile hits point P, find the horizontal and the vertical components of its velocity. Express your answers using three significant figures separated by a comma. h =15 m ΑΣφ. ? Vx , Vy = m/s
Expert Solution
Step 1

PART A:

Given, Initial velocity, vo = 59 m/s

Angle, θ = 35o

Height, yo = 115 m

g = 10 m/s2

The components of vo are given by,

x-component, vox = vocosθ = 59 x cos 35= 48.32 m/s

y-component, voy = vosinθ = 59 x sin 35= 33.84 m/s

When the object impacts, its height is 0,

From y = y+ voyt - 12gt2 , we get

0 = y+ voyt - 12gt2

5t2+33.84t+115 = 0

t = 9.25 s, or t= -2.48 s

The projectile reaches the ground in 9.25 s.

 

 

 

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