A proton (charge = +1.602 x 10-19 C, mass parallel plate apparatus. The electricity used to charge the plate is switched on so that the plate next to the proton becomes positively charged. The particle accelerates and collides with the negative plate at 6.6 x 105 m/s. a. Calculate the potential energy required to accomplish this. (EE = 3.64 x 10-16 J) b. Calculate the proton's velocity half way between the positive and negative plates. (v = 4.67 x 105 m/s) 1.67 x 10-27 kg) is at rest next to a plate in a %3D

College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter16: Electrical Energy And Capacitance
Section: Chapter Questions
Problem 7P: Oppositely charged parallel plates are separated by 5.33 mm. A potential difference of 600. V exists...
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1. A proton (charge = +1.602 x 10-19 C, mass =
parallel plate apparatus. The electricity used to charge the plate is switched on so
that the plate next to the proton becomes positively charged. The particle
accelerates and collides with the negative plate at 6.6 x 105 m/s.
a. Calculate the potential energy required to accomplish this. (Ee = 3.64 x 10-16 J)
b. Calculate the proton's velocity half way between the positive and negative
plates. (v = 4.67 x 105 m/s)
1.67 x 10-27 kg) is at rest next to a plate ina
Transcribed Image Text:field 1. A proton (charge = +1.602 x 10-19 C, mass = parallel plate apparatus. The electricity used to charge the plate is switched on so that the plate next to the proton becomes positively charged. The particle accelerates and collides with the negative plate at 6.6 x 105 m/s. a. Calculate the potential energy required to accomplish this. (Ee = 3.64 x 10-16 J) b. Calculate the proton's velocity half way between the positive and negative plates. (v = 4.67 x 105 m/s) 1.67 x 10-27 kg) is at rest next to a plate ina
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