A proton initially has v = 3.0i – 9.0 j + 2.0k and then 4.0 s later has v = -9.0i – 9.0j + 3.0k (in meters per second). (a) For that 4.0 s, what is the proton's average acceleration aava in unit-vector notation? ava = -1.5i – 0.25k m/s² (b) For that 4.0 s, what are the magnitude and direction of aavg? magnitude 1.52 X m/s² direction -189.5 ° (from the +x axis in the xz plane)

A proton initially has v = 3.0i – 9.0 j + 2.0k and then 4.0 s later has v = -9.0i – 9.0j + 3.0k (in meters per second). (a) For that 4.0 s, what is the proton's average acceleration aava in unit-vector notation? ava = -1.5i – 0.25k m/s² (b) For that 4.0 s, what are the magnitude and direction of aavg? magnitude 1.52 X m/s² direction -189.5 ° (from the +x axis in the xz plane)

Name: i followed examples in the textbook but i still am deducing the wrong
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Description: i followed examples in the textbook but i still am deducing the wrong answer :( but somehow i’m getting the right direction value A proton initially has v = 3.0i – 9.0 j + 2.0k and then 4.0 s later has v = -9.0i – 9.0j + 3.0k (in meters per second).(

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter4: The Laws Of Motion

Section: Chapter Questions

Problem 54P: A student is asked to measure the acceleration of a glider on a frictionless, inclined plane, using...

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