A proton is placed at rest in an electric field of 510 N/C. Calculate the speed of the electron 47.0 ns after being released ( e = 1,6 x 10-19C,€o =8,85 × 10¬12c²/N.m², mej= 9,11 × 10-31kg, m, = 1,67 x 10-27kg)

Physics for Scientists and Engineers, Technology Update (No access codes included)
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ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter39: Relativity
Section: Chapter Questions
Problem 39.77AP: The cosmic rays of highest energy are protons that m have kinetic energy on the order of 1013 MeV....
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A proton is placed at rest in an electric field of 510 N/C. Calculate the speed of the
electron 47.0 ns after being released (
e = 1,6 x 10-19C,€o =8,85 × 10¬12c²/N.m², mej= 9,11 × 10-31kg,
m, = 1,67 x 10-27kg)
Transcribed Image Text:A proton is placed at rest in an electric field of 510 N/C. Calculate the speed of the electron 47.0 ns after being released ( e = 1,6 x 10-19C,€o =8,85 × 10¬12c²/N.m², mej= 9,11 × 10-31kg, m, = 1,67 x 10-27kg)
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