A random sample of 120 adults showed that 42 are already fully vaccinated. Give a 95% confidence interval for the TRUE proportion of adults who are fully vaccinated. O [0.22,0.44] O [0.32,0.52] O [0.26,0.40] O [0.26, 0.44]

Q: It was observed that 30 of the 100 randomly selected students smoked. Find the confidence interval…

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Q: A sociologist is interested in surveying workers in computer-related jobs to estimate the proportion…

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Q: In a survey of 500 potential jurors, one study found that 350 were regular watchers of at least one…

A: It is given that sample size (n) is 500 and x is 350.

Q: A department store finds that in a random sample of 200 customers, 60% of the sampled customers had…

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Q: In a survey of 650 randomly selected U.S. males ages 18-64, 396 say they have gone to the dentist in…

A: Given,n=650x=396p^=xnp^=396650=0.6091-p^=1-0.609=0.391α=1-0.90=0.1α2=0.05Z0.05=1.645     (from…

Q: In another pre-election poll, a pollster finds that 438 out of 600 people polled favor, Smith.…

A: Given, X = 438 N = 600 The sample proportion is given by:

Q: It was observed that 4 out of 10 randomly selected students went to the cinema. Find the 95%…

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Q: A random survey of 495 adults found that 59 had diabetes. Which of the following is a 98% confidence…

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Q: In a sample of 225 college seniors, 189 responded positively when asked if they have spring fever.…

A: Obtain the 95% confidence interval for the proportion of all college seniors who have spring fever.…

Q: Construct an 80% confidence interval for the average quantity of beer consumed at a bar on the basis…

A: It is given that  Sample mean = 52.1 Sample standard deviation, s = 4 Sample size, n = 50…

Q: In a study of 480 households, 168 households were found to have 4 cell phones. Find a 95% confidence…

A: Given: x=168 n=480 p^=xn=168480=0.35

Q: In a random sample of 500 people eating lunch at a cafeteria on various Fridays, it was found that…

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Q: When using a one-sample z-procedure to construct a confidence interval for the proportion of a…

A: When using a one sample z procedure to construct a confidence interval for the proportion of a…

Q: In a random sample of 850​ Americans, 385 reported that they work two jobs. Which of the following…

A: The known values are, The sample proportion is,

Q: In a random sample of 500 people eating lunchbat a cafeteria on various fridays, it was found that…

A: Given X=160 n=500 P=X/n

Q: A random sample of 200 BZU students shows that 80 of them have O blood type. Let p be the BZU…

A: There are totally 200 BZU students are sampled in which 80 of them have blood type. The variable p…

Q: A random sample of 75 college students of MSU is selected and 16 are found to have motorcycles on…

A: From the given information, The sample size is 75. Out of 75 students, 16 are found to have…

Q: A random sample of 242 elephants who are in a preserve in Kenya were selected and 85 identified as…

A: Obtain the 95% confidence interval for the difference between the proportions The 95% confidence…

Q: A simple random sample of size n is drawn from a population that is normally distributed. The sample…

A: Hello! As you have posted more than 3 sub parts, we are answering the first 3 sub-parts.  In case…

Q: In a random sample of 170 customers, 90 ordered chicken sandwitches for lunch. Construct a 94%…

A: X = 90 N = 170

Q: The workers at a certain company took a random sample of 800 manhole covers and found that 40 of…

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Q: Between 27 April 2020 and 10 May 2020, Gallup surveyed a random sample of 8,712 U.S. adults…

A: e) Given information: p^=0.24n=8712 Confidence level is 95%. From the standard normal table, the…

Q: A random sample of 200 female high school students in India showed that 110 are on Facebook. A…

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Q: A survey found that 33 of 66 randomly selected women and 37 of 66 randomly selected men follow a…

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Q: A random sample of 240 adults over the age of 40 found that 144 would use an online dating service.…

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Q: A random sample of 274 elephants who are in a preserve in Kenya were selected and 94 identified as…

A: The sample proportions are Critical values: By using the standard normal table of Z, the critical…

Q: A recent survey showed that among 650 randomly selected subjects who completed 4 years of college,…

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Q: In a random sample of visitors to a famous touristattraction, 84 of 250 men and 156 of 250 women…

A: Calculate the sample proportion of men who bought souvenirs.  Similarly, calculate the sample…

Q: In another pre-election poll, a pollster finds that 442 out of 650 people polled favor Smith.…

A: Given: Total no of people polled , n=650 No. of people favor Smith, x=442 Confidence level=95%

Q: Find a 90% confidence interval for the difference between the population means for the two…

A: Given : For Sample 1 x̄1 = 3.11 n1 = 12

Q: 6) An Internet service provider sampled 590 customers and found that 85 of them experienced an…

A: According to the given information, we have Total number of customers = 590 85 of them experienced…

Q: A study of 420,095 Danish cell phone users found that 0.0321% of them developed cancer of the brain…

A: From the provided information, Sample size (n) = 420095 Sample proportion (p̂) = 0.0321% Confidence…

Q: 5. In the past, 44% of those taking a public accounting qualifying exam have passed the exam on…

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Q: b.Suppose a similar survey will be given to vaccine-eligible people in Canada by Canadian health…

A: Given data, p=0.5 E=0.02 z-value at 95% confidence is Zc=1.96 n=?

Q: studying an anomaly in chick embryos, 50 fertilized eggs were injected with a treatment on the…

A: Given Data Sample Size, n = 50 Number of successes, x = 50-12=  38.0 Significance…

Q: Researchers investigating the new Johnson & Johnson COVID Vaccine selected a random sample of 200…

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Q: The mean and standard deviation of a random sample of 7 baby orca whales were calculated as 430…

A: Solution: Let X be the weight of all baby orca whales. From the given information, x-bar=430, S=26.9…

Q: A simple random sample of 49 8th graders at a large suburban middle school indicated that 89% of…

A: Given,sample size(n)=49sample proportion(p^)=0.891-p^=1-0.89=0.11α=1-0.95=0.05α2=0.025Z0.025=1.96…

Q: 1. Out of a sample of 150 people who walked into a fast-food restaurant, 135 said they prefer…

A: As per our guidelines we are suppose to answer only one…

Q: A researcher studying reaction time of drivers states that A 95% confidence interval for the m time…

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Q: A survey of 503 women shoppers found that 46% of them shop on impulse. What is the 99% confidence…

A: Given : Sample Size, n = 503 confidence level,c=0.99

Q: population proportion, what is the 95% confidence interval estimating the proportion of businesses…

A: Given : Sample Size, n = 673 Number of successes, x = 384 confidence level,c=0.95

Q: Which of the following conditions is NOT required to construct a 90% confidence interval for u?

A: To estimate population mean, the mean salary of full professors at American colleges and…

Q: Use the one-proportion z-interval procedure to find the required confidence interval. In a sample of…

A: Introduction: The 100 (1 – α) % confidence interval for the population proportion, p is: Here, n is…

Q: A random sample of 4000 U.S. citizens yielded 2250 who are in favor of gun control legislation.…

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Q: A study of 420,095 Danish cell phone users found that 0.0321% of them developed cancer of the brain…

A: Obtain the 90% confidence interval estimate of the percentage of cell phone users who develop cancer…

Q: From a random sample of 185 children from school G, 108 indicated they wanted to study science in…

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Q: In a random sample of 1250 adult drivers, 450 said that they would cut their driving by 10% if this…

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Q: In a random sample of 512 hospital patients, 102 were readmitted within 30 days of discharge. A 90%…

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Q: 13. In another pre-election poll, a pollster finds that 438 out of 600 people polled favor Smith.…

A: It is given that sample size (n) is 600 and x is 438.