A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 20 14 23 22 22 15 21 18 17 14 25 15 21 20 14 23 Click here for the Excel Data File Find a 90 percent confidence interval for u, assuming that the sample is from a normal population. (Round your standard deviation answer to 4 decimal places and t-value to 3 decimal places. Round your answers to 3 decimal places.) The 90% confidence interval to
Q: A random sample of 16 pharmacy customers showered the waiting times below (in minutes) 17 18 16…
A: Given information- Sample size, n = 16 Calculating sample mean and sample standard deviation using…
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 12 23 17. 14.…
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Q: A random sample of 10 parking meters in a resort community showed the following incomes for a day.…
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Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 9. 12 22 12 22…
A: Number of samples (n) = 16 9 -11.25 126.5625 20 -0.25 0.0625 12 -8.25 68.0625 18 -2.25…
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 22 14 25 15 19…
A: I will use excel to solve this question.…
Q: random sample of 16 pharmacy customers showed the waiting times below (in minutes). 27 31 17 22…
A: Use the given data to form the excel table: x (x-u) (x-μ)2 27 7.125 50.765625 31 11.125…
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 27 31 17 22 22…
A: As according to given data: The mean of the data is:…
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 9 12 22 12…
A: From the given data: x¯=20.25s=5.5678n=16 Degree of freedom=n-1=15
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 15 18 11 22…
A: Given information- Confidence level, c = 90% So, significance level, α = 0.10 Sample size, n = 16…
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 20 27 24 23…
A: The sample mean is calculated as follows: The standard deviation is calculated as follows:
Q: A random sample of 16 pharmacy customers showed the walting times below (In minutes). 16 21 20 24 17…
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Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 15 19 16 18…
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Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 21 22 22 17 21…
A: From the provided information, Sample size (n) = 16 Sample mean and sample standard deviation can be…
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A: From the given information, Sample size n =40 Sample mean, x̅=55.576 Sample standard deviation,…
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Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 20 14 23 22 22…
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Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 19 22 18 23 19…
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Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 16 11 21…
A: Step-by-step procedure to obtain the mean and standard deviation value using the Excel:In Excel…
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 2.7 31 17 22…
A: Given information- Sample size, n = 16 Calculating sample mean and sample standard deviation using…
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 20 14 22 22 15…
A:
Q: In order to determine the average weight of carry-on luggage by passengers in airplanes, a sample of…
A: Confidence interval:The (1-α) % confidence interval for population mean µ, when σ is known is given…
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 15 12 17 17 14…
A: Given,sample size(n)=16sample mean(x)=17.1875standard deviation(s)=3.6737degrees of…
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 17 18 16 20 20…
A: we wants to find the 90% confidence interval . as population parameters are unknown we use t test…
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Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 27 31 17 22…
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A: Given that,standard deviation, σ =2.02sample mean, x =6.148population size (n)=10level of…
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 21 22 14 17…
A: Number of samples (n) = 16 21 2.375 5.640625 22 3.375 11.39063 14 -4.625 21.39063 17…
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 21 22 22 17…
A: The sample data shows the waiting times of 16 pharmacy customers.
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 16 11 21 19…
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Q: 3. Consumer Reports gave the following information about the life of size AA batteries in toys. 2.3…
A: Given: n=16 a. Using the excel formula "=AVERAGE(D2:D17)" the sample mean x¯=3.575 x¯=3.575 Using…
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 16 11 21 19…
A: Solution: n = 16 sample size of pharmacy customers. x=∑i=1nxin=28416=17.75 Sample Means2=∑(xi-…
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 16 11 21 19…
A: The data shows the waiting times of 16 pharmacy customers. The confidence level is 90%.
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Q: A random sample of 16 pharmacy customers showed the walting times below (In minutes). 16 11 21 19 19…
A:
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 20 14 23 22 22…
A: x¯ = 19 ; s = 3.7238 ; n = 16
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 26 17 14 23…
A: We have given that the data, We need to find sample mean and sample standard deviation. And…
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 19 22 18 23 19…
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Q: Arandom sample of 11 observations taken from a normally distributed population produced the…
A: Given : A random sample of 11 observations taken from a normally distributed population produced the…
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 11 25 19 17 24…
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Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 17 18 16 20…
A: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 17 18 16 20…
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 20 14 23 22 22…
A: From the provided information, Sample size (n) = 16 Confidence level = 90%
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Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 15 18 11 22 23…
A: The values of mean and standard deviation are,
Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 21 22 14 17…
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Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 15 12 17 17 14…
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Q: A random sample of 16 pharmacy customers showed the waiting times below (in minutes). 19 22 18 23…
A: We want to find the CI for population mean( μ) at 90%
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- A report by the Gallup Poll stated that on average a woman visits her physician 5.8 times a year. A researcher randomly selects 20 women and obtained onto the data below.A sociologist was hired by a large city hospital to investigate the relationship between the number of unauthorized days that employees are absent per year and the distance (miles) between home and work for the employee. A sample of 10 employees was chosen, and the following data were collected. Please disregard question D in the images.A seven-year medical research study reported that women whose mothers took the drugDES during pregnancy were twice as likely to develop tissue abnormalities that might leadto cancer as were women whose mothers did not take the drug.a. This study compared two populations. What were the populations?b. Do you suppose the data were obtained in a survey or an experiment?c. For the population of women whose mothers took the drug DES during pregnancy, asample of 3980 women showed that 63 developed tissue abnormalities that might leadto cancer. Provide a descriptive statistic that could be used to estimate the number ofwomen out of 1000 in this population who have tissue abnormalities.d. For the population of women whose mothers did not take the drug DES duringpregnancy, what is the estimate of the number of women out of 1000 who would beexpected to have tissue abnormalities?
- A seven-year medical research study reported that women whose mothers took the drugDES during pregnancy were twice as likely to develop tissue abnormalities that might leadto cancer as were women whose mothers did not take the drug.a. This study compared two populations. What were the populations?b. Do you suppose the data were obtained in a survey or an experiment?c. For the population of women whose mothers took the drug DES during pregnancy, asample of 3980 women showed that 63 developed tissue abnormalities that might leadto cancer. Provide a descriptive statistic that could be used to estimate the number ofwomen out of 1000 in this population who have tissue abnormalitiesA researcher uses an anonymous survey to track the number of salmon caught in Gaspe. Based on a set of 115 surveys distributed to a select few of the many hundreds of anglers who fished Gaspe, it was determined that anglers caught an average of 2.3 salmon per week. For this study, the average of 2.3 salmon per week is an example of which one statistic parameter. population sampleAn educational study to be conducted requires a test score in the middle 60% range. If μ = 100 and σ = 15, Find the highest and lowest acceptable scores that would enable a candidate to participate in the study. Assume the variable is normally distributed.
- Chapter 6, Section 4-HT, Exercise 228 - MathPad Survival Status and Heart Rate in the ICUThe dataset ICUAdmissions contains information on a sample of 200 patients being admitted to the Intensive Care Unit (ICU) at a hospital. One of the variables is HeartRate and another is Statuswhich indicates whether the patient lived (Status=0) or died (Status=1). The computer output below shows the details of a test to determine whether mean heart rate is different between patients who lived and died. (You should not do any computations. State the hypotheses based on the output, read the p-value off the output, and state the conclusion). Two-sample T for HeartRate Status N Mean StDev SE Mean 0 160 98.5 27.0 2.1 1 40 100.6 26.5 4.2 Difference = μ (0) − μ (1) Estimate for difference: -2.12 95% CI for difference: (-11.53,7.28) T-Test of difference =0 (vs not = ): T-Value =-0.45 P-Value =0.653 DF =60Click here for the dataset associated with this question.…A seven-year medical research study reported that women whose mothers took the drugDES during pregnancy were twice as likely to develop tissue abnormalities that might leadto cancer as were women whose mothers did not take the drug.a. This study compared two populations. What were the populations?After examining these data for all the jurisdictions, someone notes that certain areas have an unusually high “percent of 18-64 yr-olds with no high school diploma.” Based on this finding, this individual concludes that the high percentages are due to the rising population of immigrants in those areas. Further, the individual argues that any estimates of the associated “percent of low-income working families” in those areas should be recalculated after removing this sub-population from the data set, as they are causing the area to “look bad”. In addition to thinking critically, use the key rules about linear regression and extrapolation to write a statistically appropriate and socially responsible response to the individual’s conclusion and argument.
- An independent research group has been studying the chances that an accident at a nuclear power plant will result in radiation leakage. The group considers that the only possible types of accidents at a reactor are fire, mechanical failure, and human error, and that two or more accidents never occur together. It has performed studies that indicate that if there were a fire, a radiation leak would occur 20 percent of the time; if there were a mechanical failure, a radiation leak would occur 50 percent of the time; and if there were a human error, a radiation leak would occur 10 percent of the time. Its studies have also shown that the probability of A fire and a radiation leak occurring together is 0.0010. A mechanical failure and a radiation leak occurring together is 0.0015. A human error and a radiation leak occurring together is 0.0012. (a)What are the respective probabilities of a fire, mechanical failure, and human error? (b)What are the respective probabilities that a…Suppose that in the previous semester, the percentages of students in the five sections of ECO 204 were 20%, 21%, 19%, 15% and 25%. However, in the current semester, among a sample of 200 students, the student distribution among five sections is 51, 49, 30, 20 and 50. Can we conclude that there has been a statistically significant change in the student proportions?A recent survey conducted by Gallup (an analytic and advice firm) estimated that 50% of students in Massachusetts prefer learning full-time in person, while the remaining 50% prefer a full-time remote or a hybrid arrangement. Suppose we assume that, among USC students, the proportion of those who prefer learning full-time in person instruction is the same as that estimated by Gallup for Massachusetts. We interview a random sample of 70 USC students regarding their preferences over full-time in person versus remote/hybrid instruction. c) Under our assumption that the preferences of USC students are the same as those estimated by Gallup for Massachusetts, using the approximation based on the Normal distribution, what is the sampling distribution of the proportion of interviewed students who prefer full-time in person instruction? d) Under our assumption that the preferences of UCI students are the same as those estimated by Gallup for Massachusetts, using the approximation based on…