A random sample of 49 shoppers showed that they spend an average of $23.45 per visit and the Saturday Mornings Bookstore. The standard deviation of the population is $2.80. Find a point estimate for the population mean.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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ISBN:9780079039897
Author:Carter
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Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 26PFA
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1. A random sample of 49 shoppers showed that they spend an average of $23.45 per visit and the
Saturday Mornings Bookstore. The standard deviation of the population is $2.80.
Find a point estimate for the population mean.
2. In a simple random sample of 125 households, the sample mean number of personal computers was
1.18. Assume the population standard deviation is 0.33.
a. Construct an 80% confidence interval for the mean number of personal computers. Round the
answer to at least two decimal places.
12.5
ide
b. What calculator function did you use to create this interval? (T-interval, Z-interval, etc.)
C. If the sample size were 95 rather than 125, would the margin of error be larger or smaller than the
result in part (a)?
d. If the confidence levels were 99% rather than 80%, would the margin of error be larger or smaller
than the result in part (a)?
Transcribed Image Text:ecimal 1. A random sample of 49 shoppers showed that they spend an average of $23.45 per visit and the Saturday Mornings Bookstore. The standard deviation of the population is $2.80. Find a point estimate for the population mean. 2. In a simple random sample of 125 households, the sample mean number of personal computers was 1.18. Assume the population standard deviation is 0.33. a. Construct an 80% confidence interval for the mean number of personal computers. Round the answer to at least two decimal places. 12.5 ide b. What calculator function did you use to create this interval? (T-interval, Z-interval, etc.) C. If the sample size were 95 rather than 125, would the margin of error be larger or smaller than the result in part (a)? d. If the confidence levels were 99% rather than 80%, would the margin of error be larger or smaller than the result in part (a)?
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