A rate is equal to 0.0200 M/s. If [A] = 0.100 M and rate = k[A]', what is the new rate if the concentration of A] is increased to 0.200 M? %3D O 0.0200 M/s O 0.0400 M/s 0.0600 M/s O 0.0800 M/s O 0.100 M/s
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- If a mixture was prepared by diluting 7.0 mL of the Blue#1 solution with water to a final volume of 10.0 mL and mixing this with 2.0 mL of diluted bleach how many seconds would it require for the mixture to have an absorbance of 0.120? Use your measured values of b and of the average rate constant, k’ to answer this question. Show all work. Pls help me out asap!!Using the data in the table, determine the rate constant of the reaction and select the appropriate units. A+2B⟶C+D Trial [?] (?) [?] (?) Rate (M/s) 1 0.360 0.290 0.0144 2 0.360 0.580 0.0144 3 0.720 0.290 0.0576 k=Using the data in the table, determine the rate constant of the reaction and select the appropriate units. A+2B⟶C+D Trial [?] (?) [?] (?) Rate (M/s) 1 0.340 0.210 0.0204 2 0.340 0.420 0.0204 3 0.680 0.210 0.0816 ?=
- Using the data in the table, determine the rate constant of the reaction and select the appropriate units. A+2B⟶C+D Trial [?] (?)[A] (M) [?] (?)[B] (M) Rate (M/s) 1 0.360 0.330 0.0164 2 0.360 0.660 0.0164 3 0.720 0.330 0.0656 ?=? Units =?A river water sample of 25°C is contaminated with diazepam with initial concentration of 5000 ppb (or ng/L) when it secondary biodegradation rate in water, Kd = 10^1.3 (cu cm/mol-sec) at 25°C and molar mass of diazepam is 284.7g/mol. What is the half life of the diazepam in hours? Note: I need right answer with clear calculations.The following results were found after completion of Part C in the Experimental procedure: 0.056 M I- and 0.048 M H2O2 were used Run Catalyst Calculated Rate of Reaction (M/s) 1 none 0.031 2 10.00mL of 0.35 M FeCl2 0.52 Assuming the Rate Law = k[I-][H2O2] 2 Calculate the value of k for run 2. Give your answer to the nearest whole number.
-  Time remaining: 00:09:04 Chemistry The hydrolysis of aspirin (ASA) was measured at 3 different temperatures and the data is shown below. Table 1: Concentration of aspirin at various timepoints and temperatures. Time (min) [ASA] (mM) at 40°C [ASA] (mM) at 50°C [ASA] (mM) at 60°C 0 5.313 5.313 5.313 10 5.033 5.044 4.175 20 4.815 4.611 3.069 30 4.633 4.175 2.243 40 4.582 3.927 1.683 50 4.400 3.706 1.352 60 4.175 3.491 0.970 Using the rate constants from questions 4-6 and the Arrhenius equation, determine Ea. Use 8.314 J/molK for R. Enter your numeric answer, no units. Do not use scientific notation. Answer Skip Exit1. Experimental data: [A] [B] Rate (M/min) 0.015. 0.015 2.95 0.025 0.015 5.61 0.015 0.025 5.82 a. What is the Rate Law (calculate the orders to 2 decimals)? b. Calculate the Rate Law Constant (use the rounded-off orders & experiment 1). c. Calculate the rate (use the rounded-off orders) when [A] = .150 M and [B] = .550 MConsider the following complex reaction: A + 2B → C whose initial rate at 25 °C was measured using three different sets of initial concentrations as listed in the following table: Trial [A](M) [B](M) Rate(M/s) 1 0.400 0.050 9.60 × 10−3 2 0.400 0.100 1.92 × 10−2 3 0.800 0.050 3.84 × 10−2 A) Write the rate law for this reaction. Use k to represent the rate constant. B) Solve for k in the above rate law. Express your answer to three significant figures. Include units for k.
- Trial 0.010 M [NaOH] 0.10M [CH3COOC2H5] Initial conductivity of NaOH solution (uS/cm) Initial rate (uS/cm)/s) 1 21.0ml 2.1 ml 1285 24.72 2 21.0 ml 2.1 ml 2399 50.32 3 21.0 ml 2.1 ml 1262 23.72 What is the order of the reaction in sodium hydroxide and ethyl acetate? Explain how you determined order for each reactant.1- In the enzymatic reaction that took place in the batch constant volume reactor, the reaction rates were measured at different initial concentrations and are given in the table below. Find the appropriate kinetic model and coefficients Substrate cconcentration (mM) 1 2 4 16 32 Reaction rate (mmol/L min) 1 1.8 3.2 6.6 7.8For the reaction A à B + C, the time required to cause a concentration change of 2.4 x 10-4 M was measured. What is the reaction order for the reaction given following data: Trial 1: [A] = 0.50 M ; Time needed is 120.0 sec Trial 2: [A] = 1.00 M ; Time needed is 30.0 sec