A researcher believes that about 71% of the seeds planted with the aid of a new chemical fertilizer will germinate. He chooses a random sample of 145 seeds and plants them with the aid of the fertilizer. Assuming his belief to be true, approximate the probability that at most 102 of the 145 seeds will germinate. Use the normal approximation to the binomial with a correction for continuity. Round your answer to at least three decimal places. Do not round any intermediate steps.

Q: Suppose that 20% of the people in a large city have used a hospital emergency room in the past year.…

A: Let p be the probability that a person used a hospital emergency room. Given that p = 0.20 Let X…

Q: Based on a poll, among adults who regret getting tattoos, 19% say that they were too young when they…

A:

Q: Use the normal approximation to the binomial to find the probability for n=,10 p=0.5 and X≥8. Round…

A:

Q: In a certain city of several million people, 5.8 % of the adults are unemployed. If a random sample…

A:

Q: Suppose that 53% of the population favors a particular candidate IP a Random sample of 55 voters is…

A: The following information has been given: The sample size is n=55. The probability of success is…

Q: A brokerage survey reports that 31% of all individual investors have used a discount broker (one…

A: Given Data : sample size,n= 120 probability of success,p= 0.31

Q: A brokerage survey reports that 28% of all individual investors have used a discount broker (one…

A:

Q: A brokerage survey reports that 29 % of all individual investors have used a discount broker (one…

A: Given, Therefore, Using normal approximation to the binomial with a correction for continuity,

Q: According to the ABC news, 45% students rented their text-book. A random sample of 500 students were…

A: Solution: Let X  represent the random variable that the number of students rented their textbook.…

Q: Suppose that 62% of all college seniors have a job prior to graduation. If a random sample of 95…

A:

Q: In a certain city of several million people, 6.2% of the adults are unemployed. If a random sample…

A:

Q: Use the normal approximation to the binomial to find the probability for =n=, 49p, 0.6and ≤X40.…

A: From the provided information, Sample size (n) = 49 Probability (p) = 0.6

Q: A survey reports that 53% of college students use Google as their search engine. If 100 students of…

A: Given,      n=100      P=0.53     Mean =nP     μ=100⁎0.53=53     Standard deviationσ=nP1-P…

Q: A brokerage survey reports that 39% of all individual investors have used a discount broker. If a…

A:

Q: Based on a poll, among adults who regret getting tattoos, 11% say that they were too young when they…

A: We have to use Binomial distribution.   Binomial distribution : Suppose X be the binomial random…

Q: In a certain city of several million people, 7.6% of the adults are unemployed. If a random sample…

A: Given: n=230p=0.076 Normal approximation is used with mean μ=np and standard deviation σ=np1-p.

Q: Use the normal approximation to the binomial to find the probability for =n=, 50p, 0.9and ≤X40.…

A:

Q: If you are given n=593n=593 and p=0.3p=0.3 for a binomial experiment, use the normal distribution to…

A: Given information: n=593 p=0.3

Q: Based on the caterer's experience, 38% of attendees to events will prefer chicken for the main dish.…

A: We have to find standard deviation for number of successes using normal approximation of binomial…

Q: . Find the probability that none of the selected adults say that they were too young to get tattoos.…

A: Given : Based on a​ poll, among adults who regret getting​ tattoos, 27​% say that they were too…

Q: Suppose that 16% of the population of the U.S. is left-handed. If a random sample of 225 people from…

A:

Q: Use the normal approximation to the binomial to find the probability for =n=, 13p, 0.5and ≥X8. Round…

A: Given that  n=13,p=0.5 and X ≥ 7.

Q: According to a study, 64% of all males between the ages of 18 and 24 live at home. (Unmarried…

A: Given,n=203p=0.64mean(μ)=np=203×0.64=129.92standard deviation(σ)=np(1-p)σ=203×0.64×1-0.64σ=6.838947

Q: Suppose that 62% of all college seniors have a job prior to graduation. If a random sample of 85…

A: Given values, n = 85 p = 0.62 x = 49 To find : P(X <= 49)

Q: The mean annual income for people in a certain city (in thousands of dollars) is 40, with a standard…

A: 1.a   Given:- meanμ =40standard deviationσ=32n=38we have to find PX<42 now , this is normaly…

Q: Suppose that 61% of all college seniors have a job prior to graduation. If a random sample of 75…

A: Given,n=75p=0.61mean(μ)=npmean(μ)=75×0.61=45.75standard deviation(σ)=np(1-p)standard…

Q: At an Ingo Armenia call center, calls come in at an average rate of one call every 4 minutes. Assume…

A: Given,A random variable X~Exponetial(λ=14)and the CDF of X isF(X)=P(X≤x)=1-e-xλ ; x≥0

Q: Consider a binomial random variable x with n = 100 and p = 0.2. Use the correction for continuity…

A:

Q: suppose that 62% of all college seniors have a job prior to graduation. If a random sample of 45…

A: Obtain the approximate probability that at least 24 have a job prior to graduation. The approximate…

Q: approximate P(x≤159)

A: Here Given for Binomial experiment n=540, p =0.33

Q: In a recent year, about 22% of Americans 14 years and older are single. What is the probability that…

A: Solution: Let X be the random variable that the number of Americans 14 years and older are single.…

Q: Based on a poll, among adults who regret getting tattoos, 12% say that they were too young when they…

A:

Q: Suppose that 63% of all college seniors have a job prior to graduation. If a random sample of 90…

A:

Q: A br v rage survey reports that 29% of all individual investors have used a discount broker (one…

A:

Q: Suppose that 56% of all college seniors have a job prior to graduation. If a random sample of 55…

A:

Q: Based on a poll, among adults who regret getting tattoos, 25% say that they were too young when they…

A: Given, n = 9 p = 0.25 q = 1-0.25 = 0.75 Let X be adults that say that they were too young to get…

Q: As in a binomial distribution, successive trials of a hypergeometric distribution are independent. O…

A:

Q: brokerage survey reports that 32% of all individual investors have used a discount broker (one that…

A: Given : sample size,n 85 probability,p 0.32

Q: 46 percent of students who made a resolution of passing college with high GPA achieved their…

A: From the provided information, Sample size (n) = 134 Probability (p) = 0.46 Using normal…

Q: Suppose that 16% of the people in a large city have used a hospital emergency room in the past year.…

A: Given data,p=16%=0.16n=145P(X≥23)=?

Q: The moment generating function of the negative binomial distribution is given by pe' m, ()=1-ge 1-…

A:

Q: According to the ABC news, 45% students rented their text-book. A random sample of 500 students were…

A: Givenp=0.45n=500x~Binomial(n=500,p=0.45)

Q: In a certain city of several million people, 6.6 % of the adults are unemployed. If a random sample…

A: Binomial approximation: The normal distribution can be used as an approximation to the binomial…

Q: Suppose that 0.6% of male professional golfers use steroids, and that Max is a male professional…

A: It is given that, P( Use steroid ) =6% =0.006 P( Not use Steroid) = 1-0.006=0.994 P( Tested negative…

Q: Use the normal approximation to the binomial to find the probability for n=50, p=0.7, and x=39.…

A: Given information n = 50 p = 0.7 x = 39 Mean µ = np = 50 x 0.7 = 35

Q: Based on a poll, among adults who regret getting tattoos, 27% say that they were too young when they…

A:

Q: Based on a poll, among adults who regret getting tattoos, 18% say that they were too young when they…

A: Hey there! Thank you for posting the question. Since your question has more than 3 parts, we are…

Q: In a certain city of several mmion people, 6.2% of the adults are unemploye If a random sample of…

A: Answer:-  P=0.062 n=250

Q: A researcher believes that about 73% of the seeds planted with the aid of a new chemical fertilizer…

A: Given,n=170p=0.73mean(μ)=npmean(μ)=170×0.73=124.1standard deviation(σ)=np(1-p)standard…

Q: According to some law in genetics, when certain types of peas are crossed, the probability that the…

A:

Contingency Table

A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.

Binomial Distribution

Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.