A researcher wanted to test an association between Diabetes Status (yes, no, borderline) and Asthma Status (yes, no). Provide an Interpretation for the following output: Chi-Square Tests Asymptotic Significance (2- Value df sided) Pearson Chi-Square 2.874 2 238 Likelihood Ratio 2.817 2 245 Linear-by-Linear Association 860 1 354 N of Valid Cases 1750 a. 0 cells (0.0%) have expected count less than 5. The minimum expected count is 15.07. Edit View Insert Format Tools 12pt v Paragraph Table BIU V
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- What is the relative risk for the association between men and women vs COVID-19 infection? What do you conclude?Which are the steps involved in the construction of explanatory bivariate tables?The data is presented in parallel format. Before running the ANOVA in Excel, you will need to put it into serial (column) format. You will need to create a categorical variable for the first factor (days) and for the second factor (time of day). This is a critical step.The data presented shows exam scores for students randomly assigned to the sections meeting on these days at these times of the day: Thursday Friday Morning Afternoon Morning Afternoon 70.878.15978.246.646.476.559.376.370 65.678.359.359.778.680.892.780.865.392.3 90.890.569.177.36977.558.677.877.558.6 63.372.854.254.472.166.26372.56672.2 Conduct a 2-way ANOVA. First, find the group means for each level of the factors. (Report answers accurate to 2 decimal places.)Days: MThursday=MThursday= MFriday=MFriday= Time of day: Mmorning=Mmorning= Mafternoon=Mafternoon= Report the results of the ANOVA for the main & interaction effects. (Report P-values accurate to 4 decimal places and…
- Á study was conducted that examined the relationship between alcohol consumption and risk of heart attack. In all, 417 men, age 40 or older, were tracked over ten years and the number of that experienced a heart attack was recorded. The participants were grouped by those who totally abstained from alcohol and those that drank moderately. For the results given in the table below, use the chi-squared test to find the p value for NHST at the .05 level. (In SPSS use the Yates continuity correction value.) Heart attack Alcohol Crosstabulation Count Alcohol Abstainer Moderate Total Heart attack No 197 192 389 Yes 9. 19 28 Total 206 211 417 Op= .090 Op= 121 !! Op=.067 Op = .048According to a CCH Unscheduled Absence survey 9 of small According to a CCH Unscheduled Absence survey, 9% of small businesses use telecommuting of workers in an effort to reduce unscheduled absenteeism. This proportion compares to 6% for all businesses. Is there really a significant difference between small businesses and all businesses on this issue? Use these data and an alpha of .10 to test this question. Assume that there were 780 small businesses and 915 other businesses in this survey. According to a CCH Unscheduled Absence survey 9 of smallExpression levels of GeneA and GeneB were measured in 10 cell lines. The researcher would like to know if expression levels of GeneA and GeneB are related.a. Use a parametric method to test if GeneA and GeneB are correlated.b. Use a non-parametric method to test if GeneA and GeneB are correlated.
- what is the meaning of weighted unifrac beta diversity and unweighted unifrac diversity? How to interpretate the data value?Blood cocaine concentration (mg/L) was determinedboth for a sample of individuals who had died fromcocaine-induced excited delirium (ED) and for a sampleof those who had died from a cocaine overdose withoutexcited delirium; survival time for people in bothgroups was at most 6 hours. The accompanying datawas read from a comparative boxplot in the article“Fatal Excited Delirium Following Cocaine Use” (J.of Forensic Sciences, 1997: 25–31). ED 0 0 0 0 .1 .1 .1 .1 .2 .2 .3 .3.3 .4 .5 .7 .8 1.0 1.5 2.7 2.83.5 4.0 8.9 9.2 11.7 21.0Non-ED 0 0 0 0 0 .1 .1 .1 .1 .2 .2 .2.3 .3 .3 .4 .5 .5 .6 .8 .9 1.01.2 1.4 1.5 1.7 2.0 3.2 3.5 4.14.3 4.8 5.0 5.6 5.9 6.0 6.4 7.98.3 8.7 9.1 9.6 9.9 11.0 11.512.2 12.7 14.0 16.6 17.8 a. Determine the medians, fourths, and fourth spreadsfor the two samples.b. Are there any outliers in either sample? Any extremeoutliers?c. Construct a comparative boxplot, and use it as abasis for comparing and contrasting the ED andnon-ED samples.A national survey was conducted to obtain information on the alcohol consumption patterns of U.S. adults by marital status. A random sample of 1772 residents 18 years old and older yielded the data displayed in the table. Using a chi-squared Test for Independence, at the 5% significance level, do the data provide sufficient evidence to conclude that an association exists between marital status and alcohol consumption?
- The data in the attached image represents blood pressure based on a new trial medication used in an experiment involving a total of 50 male and female subjects. There were two levels of treatment: 0 = placebo and 1 = treatment group. Family History Blood Pressure = Fam-Hist-BP; from the paternal side = PS; from the maternal side = MS; from both sides = BS; none on both sides or not known = N.; Blood pressure before the experiment = BP-Before-Exp; Blood pressure after the experiment = BP-After-Exp. Task: Find the mean and standard deviation for the family history group, the before treatment group, and the after treatment group.The data in the attached image represents blood pressure based on a new trial medication used in an experiment involving a total of 50 male and female subjects. There were two levels of treatment: 0 = placebo and 1 = treatment group. Family History Blood Pressure = Fam-Hist-BP; from the paternal side = PS; from the maternal side = MS; from both sides = BS; none on both sides or not known = N.; Blood pressure before the experiment = BP-Before-Exp; Blood pressure after the experiment = BP-After-Exp. Task: Construct a side-by-side boxplot to compare the variables BP-Before-Exp and BP-After-Exp.The data in the attached image represents blood pressure based on a new trial medication used in an experiment involving a total of 50 male and female subjects. There were two levels of treatment: 0 = placebo and 1 = treatment group. Family History Blood Pressure = Fam-Hist-BP; from the paternal side = PS; from the maternal side = MS; from both sides = BS; none on both sides or not known = N.; Blood pressure before the experiment = BP-Before-Exp; Blood pressure after the experiment = BP-After-Exp. Task: Construct a scatterplot to display the relationship and find the correlation between age and BP-Before Exp.