A researcher wants to estimate the proportion of depressed individuals taking a new anti-depressant drug who find relief. A random sample of 225 individuals who had been taking the drug is questioned; 166 of them found relief from depression. Based upon this, compute a 95 % confidence interval for the proportion of all depressed individuals taking the drug who find relief. Then find the lower limi and upper limit of the 95 % confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a list of formulas.) Lower limit: Upper limit:

A First Course in Probability (10th Edition)
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Author:Sheldon Ross
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A researcher wants to estimate the proportion of depressed individuals taking a new anti-depressant drug who find relief. A random
sample of 225 individuals who had been taking the drug is questioned; 166 of them found relief from depression. Based upon this,
compute a 95% confidence interval for the proportion of all depressed individuals taking the drug who find relief. Then find the lower limit
and upper limit of the 95 % confidence interval.
Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a
list of formulas.)
Lower
limit:
Upper
limit:
Transcribed Image Text:A researcher wants to estimate the proportion of depressed individuals taking a new anti-depressant drug who find relief. A random sample of 225 individuals who had been taking the drug is questioned; 166 of them found relief from depression. Based upon this, compute a 95% confidence interval for the proportion of all depressed individuals taking the drug who find relief. Then find the lower limit and upper limit of the 95 % confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. (If necessary, consult a list of formulas.) Lower limit: Upper limit:
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