A resistor and an unknown device are connected in series with an AC generator as shown in the diagram below. The current leads the voltage of the generator by 63°. ww (a) If the total impedance of the circuit is 133 2, what is the value of the resistor in the circuit? Ω (b) What is the reactance of the device? Ω

A resistor and an unknown device are connected in series with an AC generator as shown in the diagram below. The current leads the voltage of the generator by 63°. ww (a) If the total impedance of the circuit is 133 2, what is the value of the resistor in the circuit? Ω (b) What is the reactance of the device? Ω

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter15: Alternating-current Circuits

Section: Chapter Questions

Problem 62CP: A 1.5k resistor and 30-mH inductor are connected in series, as below, across a120-V(rms)ac power...

See similar textbooks

Similar questions

For an RLC series circuit, the voltage amplitude and frequency of the source are 100 V and 500 Hz, respectively; R=500 ; and L = 0.20H . Find the average power dissipated in the resistor for the following values for the capacitance: (a) C=2.0F and (b) C=2.0F .
Calculate the reactance of a 5.0F capacitor at (a) 60 Hz, (b) 600 Hz, and (c) 6000 Hz.
In an RLC series circuit, the voltage amplitude and frequency of the source are 100 V and 500 Hz, respectively, an R = 5O0. L=0.20H, and C=2.0F . (a)What is the impedance of the circuit? (b) What is the amplitude of the current from the source? (C) If the emf of the source Is given by v(tt)=(100V)sin , how does the current vary with time? (d) Repeat the calculations with C changed to 0.20F .
A 1.5k resistor and 30-mH inductor are connected in series, as below, across a120-V(rms)ac power source oscillating at 60-Hz frequency. (a) Find the current in the circuit. (b) Find the voltage drops across the resistor and inductor. (C) Find the impedance of the circuit. (d) Find the power dissipated in the resistor. (e) Find the power dissipated in the inductor. (1) Find the power produced by the source.
A 700-pF capacitor is connected across an ac source with a voltage amplitude of 160 V and a frequency of 20 kHz. (a) Determine the capacitive reactance of the capacitor and the amplitude of the output current of the source. (b) If the frequency is changed to 60 Hz while keeping the voltage amplitude at 160 V, what are the capacitive reactance and the current amplitude?
A series RLC circuit has resistance R = 50.0 and inductance L. = 0.500 H. (a) Find the circuits capacitance C if the voltage source operates at a frequency of f = 60.0 Hz and the impedance is Z = R = 50.0 . (b) What is the phase angle between the current and the voltage?
At 1000 Hz, the reactance of a 5.0-mH inductor is equal to the reactance of a particular capacitor. What is the capacitance of the capacitor?
An ac source of voltage amplitude 10 V delivers electric energy at a rate of 0.80 W when its current output is 2.5 A. What is the phase angle between the emf and the current?
A 40-mH inductor is connected to a 60-Hz AC source whose voltage amplitude is 50 V. If an AC voltmeter is placed across the inductor, what does it read?
A series RLC circuit has resistance R = 50.0 and inductance L. = 0.500 H. (a) Find the circuits capacitance C if the voltage source operates at a frequency of f = 60.0 Hz and the impedance is Z = R = 50.0 . (b) What is the phase angle between the current and the voltage?
An PLC series circuit with R=600 , L = 30 mH. and c=0.050F is driven by an ac source whose frequency and voltage amplitude are 500 Hz and 50 V, respectively, (a) What is the impedance of the circuit? (b) What is the amplitude of the current in the circuit? (c) What is the phase angle between the emf of the source and the current?
Check Your Understanding Show that the tins voltages across a resistor, a capacitor, and an inductor in an ac circuit where the tins current is Irmsare given by IrmsR,IrmsXC , and IrmsXL, respectively. Determine these values for the components of the RLC circuit of Equation 15.12. Pave=12t0v0cos (15.12)