# a rhombus in a rectangle that is w meter wide a perimeter of 48m. each vertexof the rhombus is a midpoint of a side of the rectangle. express the area of the rhombus as a function of the rectangle width

Question

a rhombus in a rectangle that is w meter wide a perimeter of 48m. each vertexof the rhombus is a midpoint of a side of the rectangle. express the area of the rhombus as a function of the rectangle width

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Step 1

Let l be the length of the rectangle and w be the width of the rectangle and the perimeter of the rectangle is 44 m.

The perimeter of the rectangle is 2 (l + w ) = 48.

2 (l + w ) = 48

l + w = 24

l = 24 – w

The current situation can be representing as follows.

Step 2

Find the area of the rh... help_outlineImage Transcriptionclose1 x(diagonal), x (diagonal) 2 Area of the rhombus 1 E xwx 24-w 2 1 (24w-w2) 2 24w W 2 2 =12w 2 fullscreen

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### Trigonometry 