A rocket fired straight up is tracked by an observer on the ground 1 mi away. 1 mi (a) Show that when the angle of elevation is 0, the height of the rocket (in ft) is h = 5280 tan(0). From the figure, we see that tan(0) = so mi' (tan(0)) h = mi ft = (tan(0) (tan(0)( mi 1 mi ft. (b) Complete the table to find the height of the rocket at the given angles of elevation. (Round your answers to the nearest foot.) 35° 60° 65° 80° h ft ft ft ft

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