Asked Dec 1, 2019

a rocket initially at rest, is fired vertically with an upward acceleration of 10ms/s. at an altitude of 0.5km, the engine of the rocket cuts off. what is the maximum altitude reached by the rocket ?


Expert Answer

Step 1

In the provided question the motion of the rocket is divided into 2 parts.

Part 1. The motion of the rocket with acceleration 10 m/s2.

The velocity of the rocket as a function of position can be expressed as:


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2 (10 m/s) (0.5 km) 20 (1000 m 0 2(10 m/s)(0.5 km) 1 km v =10000 m2 /s v100 m/s

Step 2

Part 2: The engine of the rocket is cutoff that is the motion is free fall. In free fall motion the acceleration is same as acceleration due to gravity (-9.8 m/s2).

In the second part of motion the final velocity of the motion...


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(0m/s =(100 m/s)+2(-9.8 m/s' )s (100 m/s) 2(9.8 m/s) 1 km (510 m) 1000 m 0.51 km


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