2/65 A rocket runs out of fuel in the position shown andcontinues in unpowered flight above the atmosphere.If its velocity in this position was 600 mi/hr, calcu-late the maximum additional altitude h acquired andthe corresponding time t to reach it. The gravita-tional acceleration during this phase of its flight is30.8 ft/sec².v = 600 mi/hrVerticalI-30%Problem 2/652/68 v=600 mi/hr = 880 ft/secQ₁ = -30.8 ft/sec²2₁. V rat;0= 880 sin 60° -30.8 t9=30.8#/sec2t = 880(0.866)30.8-Xv²=²+2ay; 0= (880 sin 60°)-2(30.8) h2h=[880(0.866)]2(30.8)= 9429 ftor h== 24.7 sec9429= 1.786 mi5280

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A rocket runs out of fuel in the position shown and continues in unpowered flight above the atmosphere. If its velocity in this position was 600 mi/hr, calcu- ate the maximum additional altitude h acquired and the corresponding time t to reach it. The gravita- ional acceleration during this phase of its flight is 30.8 ft/sec². v = 600 mi/hr Vertical 1 -30% Problem 2/65

A rocket runs out of fuel in the position shown and continues in unpowered flight above the atmosphere. If its velocity in this position was 600 mi/hr, calcu- ate the maximum additional altitude h acquired and the corresponding time t to reach it. The gravita- ional acceleration during this phase of its flight is 30.8 ft/sec². v = 600 mi/hr Vertical 1 -30% Problem 2/65

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 8P: One of the fastest recorded pitches in major league baseball, thrown by Tim Lincecum in 2009, was...

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