A sample of a substance with the empirical formula XCI2 weighs 0.5719 g. When it is dissolved in water and all its chlorine is converted to insoluble AgCl by addition of an excess of silver nitrate, the mass of the resulting AgCl is found to be 1.2191 g. The chemical reaction is XCI2 + 2 AgNO3—2AgCl + X(NO3)2 (a) Calculate the formula mass of XCI2. Formula mass XCI2 = g mol-1 (b) Calculate the atomic mass of X. Atomic mass X = g mol-1

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Chapter3: Molecules, Moles, And Chemical Equations
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A sample of a substance with the empirical formula XCI2 weighs 0.5719 g.
When it is dissolved in water and all its chlorine is converted to insoluble
AgCl by addition of an excess of silver nitrate, the mass of the resulting
AgCl is found to be 1.2191 g. The chemical reaction is
XCI₂ + 2 AgNO3-2AgCl + X(NO3)2
(a) Calculate the formula mass of XCI2.
Formula mass XCI2 =
g mol-1
(b) Calculate the atomic mass of X.
Atomic mass X =
g mol-1
Transcribed Image Text:A sample of a substance with the empirical formula XCI2 weighs 0.5719 g. When it is dissolved in water and all its chlorine is converted to insoluble AgCl by addition of an excess of silver nitrate, the mass of the resulting AgCl is found to be 1.2191 g. The chemical reaction is XCI₂ + 2 AgNO3-2AgCl + X(NO3)2 (a) Calculate the formula mass of XCI2. Formula mass XCI2 = g mol-1 (b) Calculate the atomic mass of X. Atomic mass X = g mol-1
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