A sample of laughing gas occupies 1.619 L at 57.94 psi and -44.553°C. If the volume and the temperature of the laughing gas were changed to 10.821 L at 17.912°C, what is the pressure in atm? Use the equation: P₁V₁ P₂V₂ Ti T₂ = pressure is in atm, volume is in Liter and temperature is in Kelvin I

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Chapter5: Gases
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Problem 143CWP: A certain flexible weather balloon contains helium gas at a volume of 855 L. Initially, the balloon...
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A sample of laughing gas occupies 1.619 L at 57.94
psi and -44.553°C. If the volume and the
temperature of the laughing gas were changed to
10.821 L at 17.912°C, what is the pressure in atm?
Use the equation:
P₂V₂
P₁V₁
Ti
T₂
=
pressure is in atm, volume is in Liter and
temperature is in Kelvin
I
t
Transcribed Image Text:A sample of laughing gas occupies 1.619 L at 57.94 psi and -44.553°C. If the volume and the temperature of the laughing gas were changed to 10.821 L at 17.912°C, what is the pressure in atm? Use the equation: P₂V₂ P₁V₁ Ti T₂ = pressure is in atm, volume is in Liter and temperature is in Kelvin I t
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