A sample of neon gas effuses through a pinhole at a rate of 0.49 mL/s. What will be the rate of effusion of krypton gas through the same pinhole? Graham's law of effusion is given by the equation r1 r2 = M2 M1 where r1 and r2 are the rates of effusion of gases 1 and 2, and M1 and M2 are their molar masses, respectively.
A sample of neon gas effuses through a pinhole at a rate of 0.49 mL/s. What will be the rate of effusion of krypton gas through the same pinhole? Graham's law of effusion is given by the equation r1 r2 = M2 M1 where r1 and r2 are the rates of effusion of gases 1 and 2, and M1 and M2 are their molar masses, respectively.
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter9: Gases
Section: Chapter Questions
Problem 83E: Starting with the definition of rate of effusion and Graham’s finding relating rate and molar mass,...
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A sample of neon gas effuses through a pinhole at a rate of 0.49 mL/s. What will be the rate of effusion of krypton gas through the same pinhole? Graham's law of effusion is given by the equation
r1 |
r2 |
|
where r1 and r2 are the rates of effusion of gases 1 and 2, and M1 and M2 are their molar masses, respectively.
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