A scientist discovered a new material that expands at an extremely fast rate. After studying this material for one month, she realized that its volume tripled every two days! She decided to write an equation to model the growth of this material, relating its volume in mm³ (v) to the number of hours that have elapsed (t). If she started with a volume of 76 mm³, what equation should she use to model the alarmingly fast growth of her unknown material? previously on here but wrong answer. answer choices are V(t)=76(2)^t/6 V(t)=76(3)^t/48 V(t)=76(2)^3t V(t)=76(3)^t/
A scientist discovered a new material that expands at an extremely fast rate. After studying this material for one month, she realized that its volume tripled every two days! She decided to write an equation to model the growth of this material, relating its volume in mm³ (v) to the number of hours that have elapsed (t). If she started with a volume of 76 mm³, what equation should she use to model the alarmingly fast growth of her unknown material? previously on here but wrong answer. answer choices are V(t)=76(2)^t/6 V(t)=76(3)^t/48 V(t)=76(2)^3t V(t)=76(3)^t/
Chapter10: Exponential And Logarithmic Functions
Section10.2: Evaluate And Graph Exponential Functions
Problem 10.33TI: Another researcher at the Center for Disease Control and Prevention, Lisa, is studying the growth of...
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A scientist discovered a new material that expands at an extremely fast rate. After studying this material for one month, she realized that its volume tripled every two days! She decided to write an equation to model the growth of this material, relating its volume in mm³ (v) to the number of hours that have elapsed (t). If she started with a volume of 76 mm³, what equation should she use to model the alarmingly fast growth of her unknown material?
previously on here but wrong answer.
answer choices are V(t)=76(2)^t/6
V(t)=76(3)^t/48
V(t)=76(2)^3t
V(t)=76(3)^t/2
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