A scientist is carrying out an experiment to determine the index of refraction for a partially reflective material. To do this, he aims a narrow beam of light at a sample of this material, which has a smooth surface. He then varies the angle of incidence. (The incident beam is traveling through air.) The light that gets reflected by the sample is completely polarized when the angle of incidence is 56.0°. (a) What index of refraction describes the material? n = (b) If some of the incident light (at ?i = 56.0°) enters the material and travels below the surface, what is the angle of refraction (in degrees)? in degrees °

A scientist is carrying out an experiment to determine the index of refraction for a partially reflective material. To do this, he aims a narrow beam of light at a sample of this material, which has a smooth surface. He then varies the angle of incidence. (The incident beam is traveling through air.) The light that gets reflected by the sample is completely polarized when the angle of incidence is 56.0°. (a) What index of refraction describes the material? n = (b) If some of the incident light (at ?i = 56.0°) enters the material and travels below the surface, what is the angle of refraction (in degrees)? in degrees °

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter25: Reflection And Refraction Of Light

Section: Chapter Questions

Problem 34P

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Light traveling in a medium of index of refraction n1 is incident on another medium having an index of refraction n2. Under which of the following conditions can total internal reflection occur at the interface of the two media? (a) The indices of refraction have the relation n2 n1. (b) The indices of refraction have the relation n1 n2. (c) Light travels slower in the second medium than in the first. (d) The angle of incidence is less than the critical angle. (e) The angle of incidence must equal the angle of refraction.
A light ray is incident on an interface between water (n = 1.333) and air (n = 1.0002926) from within the air. If the angle of incidence in the air is 30.0, what is the angle of the refracted ray in the water?
Consider a light ray that enters a pane of glass with air on one side and water on the other side as shown in Figure P38.21. The light ray experiences refraction at the first interface when it enters the glass from the water and again at the second interface when it exits the glass into the air. Assume the index of refraction of the glass is 1.54. For a ray of light, find the angle of incidence 1 in the water such that the ray experiences total internal reflection when it strikes the glassair interface on the other side. FIGURE P38.21
Unpolarized light in vacuum is incident onto a sheet of glass with index of refraction n. The reflected and refracted rays are perpendicular to each other. Find the angle of incidence. This angle is called Brewsters angle or the polarizing angle. In this situation, the reflected light is linearly polarized, with its electric field restricted to be perpendicular to the plane containing the rays and the normal.
Suppose light travels from water to another substance, with an angle of incidence of 10.0º and an angle of refraction of 14.9º. (a) What is the index of refraction of the othersubstance? (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?
A beam of light traveling through a liquid (of index of refraction n1 = 1.4) is incident on a surface at an angle of θ1 = 45° with respect to the normal to the surface. It passes into the second medium and refracts at an angle of θ2 = 69.5° with respect to the normal. A. What is the index of refraction of the second material? B. What is the light's velocity in medium 1, in meters per second? C. What is the light's velocity in medium 2, in meters per second?
A light beam is traveling through an unknown substance. When it strikes a boundary between that substance and the air (?air≈1),(nair≈1), the angle of reflection is 25.0∘25.0∘ and the angle of refraction is 47.0∘.47.0∘. What is the index of refraction ?n of the substance?
A scuba diver is submerged in a pool of liquid having an index of refraction n. He looks up at the sun and measures its angle theta 1 from the vertical. He then rises to the surface and again measures its angle. What value does he get for the following values: n Theta 1 1.75E+00 2.00E+01
A beam of light enters a flint glass semicircular disk with an index of refraction of ng = 1.66 at the midpoint of the flat side as shown in the figure. Determine the angle of incidence in air such that the refracted light will travel through the glass along a normal to the semicircular surface and hit a projection screen with the coordinates x = 5.50 cm and y = 18.1 cm. =___°
A block of crown glass is immersed in water as in the figure shown below. A light ray is incident on the top face at an angle of ?1 = 45.8° with the normal and exits the block at point P. (Assume that x = 3.48 cm.) (a) Find the vertical distance y from the top of the block to P. cm(b) Find the angle of refraction ?2 of the light ray leaving the block at P. °
Which of the following statements about the critical angle for the incident and transmitted rays is correct? Check All That Apply A) There is a critical angle for a light ray coming from a medium with an index of refraction 1.20 and incident on a medium that has an index of refraction 1.40.There is a critical angle for a light ray coming from a medium with an index of refraction 1.20 and incident on a medium that has an index of refraction 1.40. B) There is a critical angle for a light ray coming from a medium with an index of refraction 1.40 and incident on a medium that has an index of refraction 1.20.There is a critical angle for a light ray coming from a medium with an index of refraction 1.40 and incident on a medium that has an index of refraction 1.20. C) The critical angle is given by sinθc = nt / ni.The critical angle is given by sinθc = nt / ni. D) The critical angle is given by sinθc = ni / nt.
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