A sel A. soA A solid cylinder of diameter d. length and density p falls due to gravity inside a pipe of diameter D The clearance between the solid cylinder and the pipe is filled with a Newtonian fluid of density p and u. For this clearance fluid, the terminal velocity of the cylinder is determined to be V. assuming a linear velocity profile. However, if the clearance fluid was changed to a Newtonian fluid of density 2p and viscosity 2u, then for an assumed linear velocity profile, the terminal velocity of the cylinder was determined to be V. From the results of these experiments, one may write that (A) F, = V (C) 2 V = V, (B) V= 2 V 1 (D) V= 4 V,
A sel A. soA A solid cylinder of diameter d. length and density p falls due to gravity inside a pipe of diameter D The clearance between the solid cylinder and the pipe is filled with a Newtonian fluid of density p and u. For this clearance fluid, the terminal velocity of the cylinder is determined to be V. assuming a linear velocity profile. However, if the clearance fluid was changed to a Newtonian fluid of density 2p and viscosity 2u, then for an assumed linear velocity profile, the terminal velocity of the cylinder was determined to be V. From the results of these experiments, one may write that (A) F, = V (C) 2 V = V, (B) V= 2 V 1 (D) V= 4 V,
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:A sel A. soA A solid cylinder of diameter d. length and
density p falls due to gravity inside a pipe of diameter D.
The clearance between the solid cylinder and the pipe is filled
with a Newtonian fluid of density p and u. For this clearance
fluid, the terminal velocity of the cylinder is determined to
be V, assuming a linear velocity profile. However., if the
clearance fluid was changed to a Newtonian fluid of density
2p and viscosity 2u, then for an assumed linear velocity
profile, the terminal velocity of the cylinder was determined
to be V,. From the results of these experiments. one may
write that
(A) V, = V
(B) V= 2 V,
(C) 2 V = V,
(D) V= 4 V,
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