A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with two hoses. Let X denote the number of hoses being used on the self-service island at a particular time, and let y denote the number of hoses on the full-service island in use at that time. The joint pmf of X and Y appears in the accompanying tabulatio p(x,y) X 0 Y 1 2 0 0.10 0.03 0.02 0.06 0.20 0.05 2 0.05 0.14 0.32 (a) What is P(X 1 and Y 1) ? P(X=1 and Y 1)- (b) Compute PX ≤ 1 and Y≤ 1). P(X1 and Y≤1)= (c) Give a word description of the event (X/0 and Y/0). O One hose is in use on both islands. O One hose is in use on one island. O At most one hose is in use at both islands. O At least one hose is in use at both islands. Compute the probability of this event. P(X0 and Y/0)-[

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
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Chapter2: Systems Of Linear Equations
Section2.4: Applications
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A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with two hoses. Let X denote the number of hoses being used on the self-service island at a particular time, and let y denote the number of hoses on the full-service island in use at that time. The joint pmf of X and Y appears in the accompanying tabulation.
p(x, y)
0
1
2
x
P(X= 1 and Y 1) = [
0
(a) What is P(X= 1 and Y 1) ?
Py(y)
P(X ≤ 1 and Y≤1):
y
(b) Compute P(X≤ 1 and Y≤ 1).
1
0.10 0.03 0.02
0.06 0.20 0.08
0.05 0.14 0.32
0
(c) Give a word description of the event { X #0 and Y #0}.
O One hose is in use on both islands.
O One hose is in use on one island.
O At most one hose is in use at both islands.
O At least one hose is in use at both islands.
Compute the probability of this event.
P(X0 and Y / 0) =
(d) Compute the marginal pmf of X.
0
Compute the marginal pmf of Y.
2
1
Using p(x), what is P(X≤ 1)?
P(X ≤1)=[
2
2
(e) Are X and Y independent rv's? Explain.
OX and Y are independent because P(x, y) ‡ px(x) · Py (y).
OX and Y are not independent because P(x, y) #Px(1) - Py(Y).
OX and Y are independent because P(x, y) = Px(2).py (y).
OX and Y are not independent because P(x, y) = Px(z) Py(y).
Transcribed Image Text:A service station has both self-service and full-service islands. On each island, there is a single regular unleaded pump with two hoses. Let X denote the number of hoses being used on the self-service island at a particular time, and let y denote the number of hoses on the full-service island in use at that time. The joint pmf of X and Y appears in the accompanying tabulation. p(x, y) 0 1 2 x P(X= 1 and Y 1) = [ 0 (a) What is P(X= 1 and Y 1) ? Py(y) P(X ≤ 1 and Y≤1): y (b) Compute P(X≤ 1 and Y≤ 1). 1 0.10 0.03 0.02 0.06 0.20 0.08 0.05 0.14 0.32 0 (c) Give a word description of the event { X #0 and Y #0}. O One hose is in use on both islands. O One hose is in use on one island. O At most one hose is in use at both islands. O At least one hose is in use at both islands. Compute the probability of this event. P(X0 and Y / 0) = (d) Compute the marginal pmf of X. 0 Compute the marginal pmf of Y. 2 1 Using p(x), what is P(X≤ 1)? P(X ≤1)=[ 2 2 (e) Are X and Y independent rv's? Explain. OX and Y are independent because P(x, y) ‡ px(x) · Py (y). OX and Y are not independent because P(x, y) #Px(1) - Py(Y). OX and Y are independent because P(x, y) = Px(2).py (y). OX and Y are not independent because P(x, y) = Px(z) Py(y).
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